Subscripted assignment dimension mismatch.

Hello all,
I know this is a common error and their seem to be millions of solutions for it however I can't get my code to run. I have read all the example I can find but non seem to help. this is my code:
a1=imread('1V.png'); a2=imread('2V.png'); a3=imread('3V.png'); a(:,:,1)=a1; a(:,:,2)=a2; a(:,:,3)=a3;
for t=1:3; y=a(:,:,t); Isum=sum(y,1); [Imax, Iloc]=max(Isum); I(t)=y(:,Iloc); end
The code runs fine if I place a single value in for t, however when I run it as a loop the subscript dimensions mismatch error pops up. I want the code to give me a matrix containing all of the I values, three columns in this case.

 Respuesta aceptada

KL
KL el 11 de Dic. de 2017
Editada: KL el 11 de Dic. de 2017
imread returns a 3D matrix. If you want to read multiple images and store them in one matrix, use a 4D matrix,
for k = 1:3
a(:,:,:,k) = imread([num2str(k) 'V.png']);
%other code
end

4 comentarios

Robbie McDermott
Robbie McDermott el 11 de Dic. de 2017
Thank you for your reply!
The code tells me that the imaread matrices are all 2D though. When I say size(a1) it returns 1280 960
KL
KL el 11 de Dic. de 2017
Aha, then you're reading grayscale images. The the problem should be in assiging l(t). Change it to l(:,t)
You've been actually trying to assign a vector to a single element. Alternative is to use cell arrays. l{t}.
Robbie McDermott
Robbie McDermott el 11 de Dic. de 2017
AH! Using l(:,t) has fixed it! Thank you very very much! that will save me a lot of time!
Thank you so much, very very much appreciated!!
KL
KL el 11 de Dic. de 2017
Editada: KL el 11 de Dic. de 2017
You're very welcome!
Another tip: Always try to preallocate your matrices before loop, this would greatly improve your code's performance. For example,
l = zeros(256,3);

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el 11 de Dic. de 2017

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KL
el 11 de Dic. de 2017

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