How to check if a string contains only numbers?

39 visualizaciones (últimos 30 días)
Rahul Pillai
Rahul Pillai el 14 de Dic. de 2017
Comentada: Steven Lord el 16 de Abr. de 2025
Is there any expression for this ? For example :
-100 should return 1
a100b should return 0
0.1256 should return 1 and so on

Respuesta aceptada

Walter Roberson
Walter Roberson el 14 de Dic. de 2017
The easiest way is to check if str2double() returns nan. Otherwise you need to parse the string and there are a number of odd cases to account for in scientific notation.
Note: if you do use str2double() you should give some consideration as to what result you want for complex numbers, whether those are to be treated as numeric or as invalid because of the 'i' or 'j' present.
  7 comentarios
Walter Roberson
Walter Roberson el 16 de Abr. de 2025
Hah, yes,
nan == nan
ans = logical
0
nan >= nan
ans = logical
0
nan < nan
ans = logical
0
all returning false is an oddity of floating point numbers. Oddly enough,
nan ~= nan
ans = logical
1
returns true, so an alternate way to test for nan is
x ~= x
Steven Lord
Steven Lord el 16 de Abr. de 2025
I would not describe the behavior of the relational operators with one of the inputs being NaN an "oddity". It's how NaN is defined to work in the IEEE 754 specification, as summarized on the NaN Wikipedia page. In IEEE 754-2019 it's section 5.11. A short excerpt:
"Four mutually exclusive relations are possible: less than, equal, greater than, and unordered; unordered arises when at least one operand is a NaN. Every NaN shall compare unordered with everything, including itself."
If you want to tell if something is a NaN and don't want to use isnan or ismissing for whatever reason, you could use isequaln instead of isequal. isequaln explicitly treats NaN as equal to NaN.

Iniciar sesión para comentar.

Más respuestas (0)

Categorías

Más información sobre Data Type Conversion en Help Center y File Exchange.

Etiquetas

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by