Finding equal members in a vector
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Hi. My question is how can I find equal members in a vector with their indices.
For example I have this vector.
V = [ 10 13 10 20 10 95 70 13];
Thanks a lot.
1 comentario
Image Analyst
el 17 de Dic. de 2017
This has nothing to do with the MATLAB compiler product or the Coder product, or a GUI or 3-D plots, or nearly all the tags you applied. Save yourself some time and only put the relevant tags that will help people.
Respuestas (4)
jean claude
el 17 de Dic. de 2017
find(x==10)
2 comentarios
mr mo
el 17 de Dic. de 2017
jean claude
el 17 de Dic. de 2017
Editada: jean claude
el 17 de Dic. de 2017
[a] = histc(x,unique(x));
t=unique(x);
c=find(a>1);
d=0;
for i=1:length(c);
d=[d find(x==t(c(i)))];
end
d(1)=[]; % d is the output
Star Strider
el 17 de Dic. de 2017
If you only want the repeated values in the vector and their indices:
V = [ 10 13 10 20 10 95 70 13]; % Original Vector
[Vu,~,I] = unique(V(:), 'stable'); % Unique Values
Tally = accumarray(I, 1); % Count Occurrences
Idx = bsxfun(@eq, V, Vu(Tally > 1)) .* (1:length(V)); % Determine Indices Of Multiple Values Only
OutD = [Vu(Tally > 1) Idx] % Double Matrix Result
for k1 = 1:size(Idx,1)
IdxC{k1} = Idx(k1,(Idx(k1,:)>0)); % Keep Only Non-Zero Values
OutC{k1} = {OutD(k1,1) IdxC{k1}}; % Cell Array Result
end
celldisp(OutC) % View Cell Array (Optional)
OutD =
10 1 0 3 0 5 0 0 0
13 0 2 0 0 0 0 0 8
The ‘OutC’ cell array result eliminates the zeros in the ‘(2:end)’ columns of ‘OutD’.
4 comentarios
mr mo
el 17 de Dic. de 2017
Star Strider
el 17 de Dic. de 2017
You did not say the line that threw that error.
My code ran for me without error in R2017b, with the default ‘automatic expansion’.
Use these nested bsxfun calls instead:
Idx = bsxfun(@times, bsxfun(@eq, V, Vu(Tally > 1)), (1:length(V)));
mr mo
el 17 de Dic. de 2017
Star Strider
el 17 de Dic. de 2017
Not that I am aware of. It is necessary to accumarray (or one of the histogram functions) to count the occurrences. Using bsxfun is necessary to do the array calculations.
Jos (10584)
el 17 de Dic. de 2017
V = [ 10 13 10 20 10 95 70 13];
[VU, ~, j] = unique(V)
P = accumarray(j, 1:numel(V), [] ,@(x) {x})
% P{k} holds all the indices where V equals VU(k)
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