How to add two probability density functions efficiently

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Hello,       I have a simple problem but I need to improve the execution efficiency when I have thousands of data in a probability density function, a small example:
close all
clear
%example
x =[ 1 3 5 9 15];
y =[ 4 7 8 12 6];
xn=[ 3 9 16];
yn=[ 10 3 4];
[xnew,ynew]=add2pdf(x,y,xn,yn);
xnew
ynew
% function
function [xnew,ynew]=add2pdf(x,y,xn,yn)
% sum two probability density function
[nf,nc]=size(xn);
xold=x;
yold=y;
xx=[x xn];
[xv,xp]=sort(xx,'ascend');
dxv=diff(xv);
xnew=[xv(1) xv(find(dxv>0)+1)];
ynew=zeros(1,length(xnew));
for i=1:size(y,2),
pynew=find(xnew==xold(i)); % <====this instruction it's very slow (find), but I need the pointers
ynew(pynew)=y(i);
end
for i=1:length(xn),
px=find(xnew==xn(i));
ynew(px)=ynew(px)+yn(i);
end
return

Respuesta aceptada

David Goodmanson
David Goodmanson el 20 de Dic. de 2017
Editada: David Goodmanson el 20 de Dic. de 2017
Hi Juan,
Here is one way. It takes advantage of the fact that when you make a sparse matrix with repeated indices, the corresponding values get added. Here M is a one-row matrix.
M = full(sparse([x xn],1,[y yn]))';
xnew = find(M);
ynew = M(xnew);
  3 comentarios
Juan Pablo Segovia
Juan Pablo Segovia el 20 de Dic. de 2017
David, Great solution for integers numbers, fast, efficient and elegant. Thank you very much.
David Goodmanson
David Goodmanson el 20 de Dic. de 2017
Juan, you're welcome, thank you for your comment. The sparse function has useful properties and did most of the work here.

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