Returning Variables as Characters

I have function such that

a= rand (1,10); % it generates random real numbers from 0 to 1 
i=1:10;
if b(i)< 0.4; 
b(i)= 'A'; 
else if 
b(i) = 'B'
end

the purpose of this code is for example

b = 0.23 0.45 0.89 0.74 0.48 0.98 0.12 0.05 0.56 0.14

I want it to return as a result

b= A B B B B B A A B A

[Guillaume]

@Dogukan,

We really don't appreciate when the original poster edit their question away once they've got an answer. This is not a private consulting service. The answers we post are not just for you, they're intended to help anybody with the same issue. If you edit the question away, the answers become meaningless.

It also makes us a lot less likely to answer your questions in the future.

Thankfully, MathWorks doesn't like it either and have a policy of restoring questions edited away to their original state, so it's also pointless.

[Rena Berman]

(Answers Dev) Restored edit

Answer 1

[Stephen23]

method one: character code:

>> b = char(66-(a<0.4))
b = ABBBBBAABA

method two: sprintf:

>> b = sprintf(' %c',66-(a<0.4))
b =  A B B B B B A A B A

method three: indexing (char):

>> c = 'AB';
>> b = c(2-(a<0.4))
b = ABBBBBAABA

method four: indexing (cell):

>> c = {'A','B'}65_66
>> b = c(2-(a<0.4))
b = 'A' 'B' 'B' 'B' 'B' 'B' 'A' 'A' 'B' 'A'

method five: generate characters directly using randi:

>> char(randi([65,66],1,10))
ans = ABBBBBAABA

Answer 2

[Pawel Jastrzebski]

clear all;
clc;

data = rand (1,10)

%logical vector to establish when datapoint is 'A' and 'B'

% Condition 1: 'A' if 'data <= 0.5'
% Condition 2: 'B' if 'data >  0.5'
logicValA = data <= 0.5;
logicValB = data > 0.5;

% Use logical vectors to separate 'data' into 'A's' and 'B's':

% 'newData' as 'char vector' → all values concatenated
newData(logicValA) = 'A'
newData(logicValB) = 'B'

% 'newData1' as 'cell array' → all values separated
newData1 = {}
newData1(logicValA) = {'A'}
newData1(logicValB) = {'B'}

[Trevor Badji]

clear all;
clc;
N=10;
probVector = [0.4 0.05 0.2 0.15 0.2];
b = rand (1,N)
%logical vector
% 'A' if 'data <= 0.5'
% 'B' if 'data >  0.5'
logicValA =  0<b<=probVector(1);
logicValB =  probVector(1)< b <probVector(1)+probVector(2);
logicValC =  probVector(1)+ probVector(2)<b<= probVector(1)+probVector(2)+probVector(3);
logicValD =  probVector(1)+ probVector(2)+probVector(3)<b<=probVector(1)+probVector(2)+probVector(3)+probVector(4);
logicValE =  probVector(1)+probVector(2)+probVector(3)+probVector(4)<b<= probVector(1)+probVector(2)+probVector(3)+probVector(4)+probVector(5);

% 'newData' as 'char vector' → all values concatenated
newData(logicValA) = 'A'
newData(logicValB) = 'B'
newData(logicValC) = 'C'
newData(logicValD) = 'D'
%newData(logicValE) = 'E'
% 'newData1' as 'cell array' → all values separated
newData1 = {}
newData1(logicValA) = {'A'}
newData1(logicValB) = {'B'}
newData1(logicValC) = {'C'}
newData1(logicValD) = {'D'}
newData1(logicValE) = {'E'}

I have changed my code regarted to yours but now it only returns E what is the missing point ?

[Walter Roberson]

A<B<C means to compare A and B first getting out 0 (false) or 1 (true), and then to compare that 0 or 1 to C. You need to test A<B&B<C