how can replace randi instead randint?
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hi ;i have a question please help me , i want to replace randi instead randint in ofdm_basic code in r2017a , but i dont know how i must do it . please answer and help me . this is that line :
X=randint(1,Nused*Nframe,M); % bit: integer vector
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Más respuestas (5)
Geoff Hayes
el 2 de En. de 2018
mohamad - which ofdm_basic code are you referring to? Is this something found on the MATLAB FileExchange or something else? From Communications System Toolbox Release Notes, it looks like randint has been removed from the Communications System Toolbox and is to be replaced with randi.
If we assume that the code
X=randint(1,Nused*Nframe,M)
creates a 1x(Nused*Nframe) matrix with integers in the interval [0,M-1], then we can replace the above with
X = randi(M, 1, Nused*Nframe) - 1;
I think that will work...
4 comentarios
mohamad gholami
el 2 de En. de 2018
Editada: Geoff Hayes
el 2 de En. de 2018
Geoff Hayes
el 2 de En. de 2018
ok, so try replacing with the line
X = randi(M, 1, Nused*Nframe) - 1;
I subtract one since randi will generate integers from the interval [1,M] and not the [0,M-1] that randint seems to be using.
mohamad gholami
el 2 de En. de 2018
Geoff Hayes
el 3 de En. de 2018
Mochan Yang
el 22 de Jul. de 2019
0 votos
bitstream=randi(2,1,N)-1
1 comentario
Walter Roberson
el 22 de Jul. de 2019
bitstream = randi([0 1], 1, N);
or
bitstream = rand(1,N) >= 0.5;
Yusuf lamah
el 22 de Mzo. de 2020
0 votos
thank you very much
khalil nasri
el 6 de Mzo. de 2021
0 votos
randn( )>0;
1 comentario
Walter Roberson
el 6 de Mzo. de 2021
Normal distribution has peak probability at 0 exactly. Does testing for strict greater than give 50% exactly?
HONG CHENG
el 28 de Abr. de 2022
you can look at this link
Specifically
You just need to change the order of paramters
a=randint(3,4,[1,4]);
a=randi([1,4],3,4);
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