how to most efficiently solve equation?

Hi, I have the following data (see file attached)

f 8594x93 matrix w 8594x1 vector z 1x93 vector

I want to now find a vector w1 (8594x1) such that w1' * f = z. Asked differently, how does w1 need to look if when multiplied with f gives exactly z?

What is the most efficient way of setting this up in Matlab? Thanks GonzalesSpeedy

Answer 1

[Matt J]

 w1= z/f

Answer 2

[SpeedyGonzales]

thanks. That was easy!

[Matt J]

You're welcome but please click accept on my answer if it resolved your problem.

[Roger Stafford]

It is important to realize that your problem is the equivalent of having 93 linear equations in 8594 unknowns. Consequently the solution obtained by z/f will be far from unique. In fact it probably has some 8501 degrees of freedom. Matlab uses a kind of "least-squares" optimization in making its selection out of all these possibilities. See the website:

https://www.mathworks.com/help/matlab/ref/mrdivide.html

[Matt J]

SpeedyGonzales' comment moved here:

Thank you Roger for your comment. For the time being it is not ultimately important to have the optimal solution, just one that satisfies my conditions suffices.