Root Mean Square Value of Histogram

15 visualizaciones (últimos 30 días)
Amy Wong
Amy Wong el 15 de En. de 2018
Comentada: Image Analyst el 17 de En. de 2018
How do I find the root mean square value of this histogram?
The data is Histo = [1;47;56;1298;9770;1114;0;0;2]

Respuesta aceptada

Rik
Rik el 15 de En. de 2018
Editada: Rik el 15 de En. de 2018
If you don't have the original data, you can approximate it with the code below.
Histo = [1;47;56;1298;9770;1114;0;0;2]
centers=-4:4;
mean_of_squared_values=sum(Histo.*(centers(:).^2))/sum(Histo);
RMS=sqrt(mean_of_squared_values);
This works because the mean is the sum divided by the count.
  6 comentarios
Amy Wong
Amy Wong el 17 de En. de 2018
Editada: Amy Wong el 17 de En. de 2018
I know that the RMS is to find the Standard Deviation of the histogram. Do I use the RMS of the original data values or the RMS the bin locations?
Image Analyst
Image Analyst el 17 de En. de 2018
I'm guessing you overlooked my answer below. We don't know which of the 3 RMS values you want. Only you know that. Maybe if you told us what you wanted to do with that information we could guide you.

Iniciar sesión para comentar.

Más respuestas (1)

Image Analyst
Image Analyst el 15 de En. de 2018
Amy:
I just want to make sure you realize that the RMS of the original data values is not the same as the RMS of the bin locations (what Rik gave you), and neither is the same as the RMS of the bin heights. Yo DO know that don't you? So, which do you want? I give an illustration of all 3 in the demo code below, and you can see how they're different.
r = randn(20);
h = histogram(r)
counts = h.Values'
edges = h.BinEdges'
binCenters = (edges(1:end-1) + edges(2:end))/2
mean_of_squared_values = sum(counts.*(binCenters.^2))/sum(counts);
% Compute the RMS value of the bin center locations.
rmsCenters = sqrt(mean_of_squared_values)
% Compute the RMS value of the bin heights (counts).
rmsCounts = rms(counts)
% Compute the RMS of the actual data values.
rmsValues = rms(r(:))
% They're not the same!

Categorías

Más información sobre Histograms en Help Center y File Exchange.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by