Phase shift between two signals with cross-correlation

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salvor
salvor el 17 de En. de 2018
Comentada: Star Strider el 18 de En. de 2018
Good afternoon everyone. I have two time signals representing vibration measurements from two sensors and I would like to know the phase shift between them. These two signals come from a rotating device. My idea is to use cross-corelation between them so that I can find the time lag but I have a few questions:
1. Do I have to filter out the noise in the signals?
2. The signals contain a dominant harmonic and multiple of it + other harmonics. Can I still use xcorr? As I have seen many applications on the web and on this forum but all ofthem are for deterministic/pure waves signals.
If you need any additional information to answer just let me know.
Thank you

Respuesta aceptada

Star Strider
Star Strider el 17 de En. de 2018
You will have to experiment with your signals to see if filtering them is necessary. If you get acceptable results without filtering, you can obviously avoid that step.
Filtering has its own problems if you are interested in the phase relationships. If you are using an IIR filter, use the filtfilt function to do the filtering, since it is phase-neutral for all filters. (It is not necessary for zero-phase FIR filters, and you can use filter with them.)
Two Signal Processing Toolbox functions that you may find helpful are finddelay (link) and alignsignals (link). (I believe these were introduced in R2015. The documentation does not say specifically.)
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salvor
salvor el 18 de En. de 2018
Editada: salvor el 18 de En. de 2018
Hi! Using the command finddelay I get the same result as looking at the time lag of the maximum covariance (using xcorr). What I do not understand is the meaning of this values. Since my signal is a summation of multiple waves, is that value some sort of avarage delay?
Star Strider
Star Strider el 18 de En. de 2018
I am not certain. For a full explanation of what finddelay does and how it works, I refer you to the documentation section on Algorithms (link).

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