Sub values into multiple rows and columns simutaneously

I have a 10x10 matrix. I want to sub a few values into the matrix simultaneously, with the other values being zero. It would be time-consuming to sub the values one by one. Is there any way to do this?
For example, A=[zeros(10,10)] A(1,1)=-4 A(2,2)=-4 A(3,3)=-4
Is there a way to sub -4 into these locations at once?

1 comentario

Jan
Jan el 19 de En. de 2018
Does "to sub" mean "subtract" or "substitute"? According to your code "substitute" is meant.

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Jan
Jan el 19 de En. de 2018
Replacing 3 elements is not time consuming and the show code is very efficient. If run time is critical, you are working on another problem, obviously. Then it is better to explain the real problem, and not a very simplified version of it, which omits the actual time consuming details.
If you want to replace some thousands of elements, whose indices are store in two vectors:
x = [1,2,3]; % Can be much longer
y = [1,2,3];
index = sub2ind(size(A), x, y);
A(index) = -4;

Más respuestas (2)

Walter Roberson
Walter Roberson el 19 de En. de 2018
Use sub2ind convert the row column pairs into linear indexing. Then index the left side with the linear indexes.
The words " a few" and " others remaining zero" might indicate that you also could use SPARSE matrices. For instance:
A = sparse([1 2 3],[1 2 3],-4,10,10)
full(A)

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el 19 de En. de 2018

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el 19 de En. de 2018

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