How to join the subelements of a cell?
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I am trying to express all sentences in one cell with string subelements.
s='I am George. John is there? Ana is around! Are you mad?'
[y,matches] = strsplit(s,{'.','?','!'})
for i = 1:length(matches)
y{i}=[y{i},matches{i}]
end
y=y(~cellfun('isempty',y))
1 comentario
Matt J
el 26 de En. de 2018
Don't think you finished your question (because I'm not sure what it is). If you're trying to rejoin all the sub-strings in y, see my answer below.
Respuestas (2)
Matt J
el 26 de En. de 2018
Editada: Matt J
el 26 de En. de 2018
s=[y{:}]
6 comentarios
Steven Lord
el 26 de En. de 2018
This is what I receive when I run the code you posted followed by Matt's suggestion.
s = 'I am George. John is there? Ana is around! Are you mad?'
[y,matches] = strsplit(s,{'.','?','!'})
for i = 1:length(matches)
y{i}=[y{i},matches{i}]
end
y=y(~cellfun('isempty',y))
s2 = [y{:}]
whos s2
s2 =
'I am George. John is there? Ana is around! Are you mad?'
Name Size Bytes Class Attributes
s2 1x55 110 char
What exactly do you need/want/expect s2 to be for this example? Be specific about the type and size you expect s2 to be and the contents you expect s2 to contain.
Domanic
el 26 de En. de 2018
Editada: Domanic
el 26 de En. de 2018
To join elements of the cell array, y, you can use:
y = cell2mat(y);
or
y = {cell2mat(y)};
for a cell array.
To more generally achieve what you're trying to do, you can use regular expressions:
expression = '(?<=\W)\s'; % Expression to find white space following punctuation
strsplit(s,expression,'delimitertype','regularexpression'); % split string around result of regexp
2 comentarios
Domanic
el 26 de En. de 2018
How about:
expression = '(?<=\W)\s';
y = strsplit(s,expression,'delimitertype','regularexpression');
y = {cell2struct(y,'substrings')};
where the strings are accessed as:
y{1}.substrings
or
y{1}.substrings(1)
not sure why you'd want this, though.
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