Issues making the table and plot output properly

Question is: Write a script file that accepts each of the four vectors as inputs. The script file should plot the data on three different graphs in the same window. The function should also display the data in a table with the following form (including the header). In this problem you’re required to use fprintf to generate the table below.

Time (s) A1 (m/s2) A2 (m/s2) A3 (m/s2)

0 0 0 0

5 7 10 9

10 11 15 13

15 19 21 17

20 15 16 22

25 14 11 25

30 17 13 21

My code: t = input('Input the initial and final time(X is start Y is end), ex:[X:5:Y]');

a1 = input('Enter A1 data ex: [0 7 11 ...]');

a2 = input('Enter A2 data ex: [0 7 11 ...]');

a3 = input('Enter A3 data ex: [0 7 11 ...]');

plot(t,a1);

hold on;

plot(t,a2);

hold on;

plot(t,a3);

hold off;

legend('A1=a1','A2=a2','A3=a3');

fprintf('%6s %6s %6s %6s\n','Time(s)','A1(m/s2)','A2(m/s2)','A3(m/s2)');

fprintf('%.3f \t %.3f \t %.3f \t %.3f\n',t,a1,a2,a3);

I am getting an incorrect plot and table, all mismatched numbers. Debugging while I wait for an answer but I feel someone else will be able to recognize the error faster than I can.

Thanks in advance ;)

Edit: This is the output I get. I feel there is an issue with the way I had the information inputted, but I havent been able to figure out how to have it print properly:

Time(s) A1(m/s2) A2(m/s2) A3(m/s2)

0.000 5.000 10.000 15.000

20.000 25.000 30.000 0.000

7.000 11.000 19.000 15.000

14.000 17.000 0.000 10.000

15.000 21.000 16.000 11.000

13.000 0.000 9.000 13.000

17.000 22.000 25.000 21.000

[Michael spillane]

The plot isnt the issue, it appears to be the way my input is formatted, as can be seen in the table on the bottom

Answer 1

[Image Analyst]

"three different graphs in the same window." could mean

subplot(2,2,1);
plot(.....
subplot(2,2,2);
plot(.....
subplot(2,2,3);
plot(.....

To get a table, you should use the uitable() function.

[Michael spillane]

What about the table? I see the correct data on it but it appears to be outputting from left to right then starting the next group of data.

[Image Analyst]

Give a field width, like 10.3 or whatever.

fprintf('%10.3f \t %10.3f \t %10.3f \t %10.3f\n',t,a1,a2,a3);

[Michael spillane]

I have tried many different ways including the suggested but my data still keeps being output as:

Time(s) A1(m/s2) A2(m/s2) A3(m/s2)

     0.000         5.000        10.000        15.000
    20.000        25.000        30.000         0.000
     7.000        11.000        19.000        15.000
    14.000        17.000         0.000        10.000
    15.000        21.000        16.000        11.000
    13.000         0.000         9.000        13.000
    17.000        22.000        25.000        21.000

Time being the 0,5,10,15,20,25,30. it appears it is putting the 7 datapoints in a row and continuing to the next row after outputting

[Image Analyst]

The tabs are messing you up. Get rid of them. Try this:

% Time (s) A1 (m/s2) A2 (m/s2) A3 (m/s2)
A=[...
0 0 0 0
5 7 10 9
10 11 15 13
15 19 21 17
20 15 16 22
25 14 11 25
30 17 13 21]

% My code:
% t = input('Input the initial and final time(X is start Y is end), ex:[X:5:Y]');
% a1 = input('Enter A1 data ex: [0 7 11 ...]');
% a2 = input('Enter A2 data ex: [0 7 11 ...]');
% a3 = input('Enter A3 data ex: [0 7 11 ...]');
t = A(:, 1)
a1 = A(:, 2)
a2 = A(:, 3)
a3 = A(:, 4)

plot(t,a1);
hold on;
plot(t,a2);
hold on;
plot(t,a3);
hold off;
legend('A1=a1','A2=a2','A3=a3');
fprintf('     Time(s)    A1(m/s2)    A2(m/s2)    A3(m/s2)\n');
fprintf('%11.3f %11.3f %11.3f %11.3f\n',t,a1,a2,a3);

[Michael spillane]

Same result, with the 0-30 added from l to r then the next group of data is output in the same way. I think there has to be something wrong with matlab if every possible solution (of my own) as well as a different format of input all give the same result.

[Michael spillane]

Ended up just making M = [t a1 a2 a3] and then

fprintf('%11.3f %11.3f %11.3f %11.3f\n',M.');

Annoying how this cant be done without this extra step

[Stephen23]

fprintf('%11.3f %11.3f %11.3f %11.3f\n',[t,a1,a2,a3].');

[Image Analyst]

That's because my a1, etc. were column vectors and your were row vectors because of the different ways we created the vectors. (I was lazy and didn't want to type in all that stuff while I was developing the code for you.)