How do I create a 3 dimensional surface from X Y Z points

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Eric Verheyen
Eric Verheyen el 9 de Mzo. de 2018
Respondida: Al Danial el 20 de Mayo de 2022
Hi all,
I am struggling a bit here, and hope somebody could help. I have a set of points from a complex function that I am trying to produce a 3D shape of, and have had no luck so far. I used Python to find the points in a .txt format. From there, I copy the data to Excel to transpose the columns into rows for Matlab use. The problem is, I can't seem to figure out a code to just take the X, Y, and Z coordinates and produce some kind of mesh grid or figure. Does anybody have a code for this?
Here is an example of just (10) points from my function. I can tell Python to produce anywhere from 10 to 10,000 points.
x = [422 424 424 422 422 421 421 425 421 424]; y = [87 96 87 87 83 93 85 88 86 91]; z = [92.73 94.88 92.92 92.73 92.04 93.92 92.24 93.23 92.42 93.78];
Best regards,
Eric.

Respuestas (3)

Star Strider
Star Strider el 9 de Mzo. de 2018
Using the griddata (link) function is an option:
x = [422 424 424 422 422 421 421 425 421 424];
y = [87 96 87 87 83 93 85 88 86 91];
z = [92.73 94.88 92.92 92.73 92.04 93.92 92.24 93.23 92.42 93.78];
figure(1)
stem3(x, y, z)
grid on
xv = linspace(min(x), max(x), 20);
yv = linspace(min(y), max(y), 20);
[X,Y] = meshgrid(xv, yv);
Z = griddata(x,y,z,X,Y);
figure(2)
surf(X, Y, Z);
grid on
set(gca, 'ZLim',[0 100])
shading interp
Experiment to get the result you want.
  6 comentarios
Star Strider
Star Strider el 19 de Mayo de 2022
@Felipe Alvarez Arroyo — My pleasure!
Votes are always appreciated!

Iniciar sesión para comentar.


Shivam Anand
Shivam Anand el 11 de Mayo de 2022
x=[32 20 67 1 98 34 57 65 24 82 47 55 8 51 13 14 18 30 37 39 10 33 21 26 38 81 83 60 95 22 17 5 72 46 99 52 12 25 96 29 70 85 43 69 19 78 97 31 89 53 2 91 48 71 61 15 36 84 94 50 11 80 6 7 49 74 9 88 40 79 27 68 73 64 63 59 86 23 35 58 45 28 100 42 93 87 16 90 41 66 54 92 77 4 62 76 75 56 3 44];
y=[96 75 24 9 83 49 27 77 3 23 17 31 40 13 7 52 51 21 98 47 64 79 78 91 44 16 15 100 84 99 63 68 70 30 54 76 97 73 33 5 88 8 71 66 62 25 60 42 72 45 18 11 28 59 89 65 10 55 69 81 12 26 20 95 87 41 74 50 93 22 43 90 14 34 82 35 56 38 80 32 1 57 6 36 37 61 29 58 2 48 4 46 67 53 92 86 94 19 39 85];
z=[55 31 11 45 83 36 86 49 15 57 42 46 8 94 88 47 54 81 98 41 32 35 56 85 9 89 37 60 23 62 67 100 78 76 73 80 10 20 68 34 77 93 1 63 53 12 22 99 91 40 84 24 33 3 43 19 92 97 6 82 64 25 26 79 95 4 44 58 5 21 70 29 65 87 96 90 51 14 18 2 72 28 71 39 52 7 27 59 50 61 48 30 66 69 17 13 74 16 75 38];
xlin = linspace(min(x), max(x), 100);
ylin = linspace(min(y), max(y), 100);
[X,Y] = meshgrid(xlin, ylin);
% Z = griddata(x,y,z,X,Y,'natural');
% Z = griddata(x,y,z,X,Y,'cubic');
Z = griddata(x,y,z,X,Y,'v4');
mesh(X,Y,Z)
axis tight; hold on
plot3(x,y,z,'.','MarkerSize',15)

Al Danial
Al Danial el 20 de Mayo de 2022
Since you're starting in Python you can make the surface plot there too if you want. This is a translation of @Star Strider's matlab solution:
#!/usr/bin/env python
import matplotlib.pyplot as plt
from matplotlib import cm
import numpy as np
from scipy.interpolate import griddata
x = np.array([422, 424, 424, 422, 422, 421, 421, 425,
421, 424])
y = np.array([87, 96, 87, 87, 83, 93, 85, 88, 86, 91])
z = np.array([92.73, 94.88, 92.92, 92.73, 92.04, 93.92,
92.24, 93.23, 92.42, 93.78])
xv = np.linspace(np.min(x), np.max(x), 20)
yv = np.linspace(np.min(y), np.max(y), 20)
[X,Y] = np.meshgrid(xv, yv)
Z = griddata((x,y),z,(X,Y),method='linear')
fig, ax = plt.subplots(subplot_kw={"projection": "3d"})
surf = ax.plot_surface(X, Y, Z, cmap=cm.coolwarm,
linewidth=0, antialiased=False)
ax.set_xlabel('X')
ax.set_ylabel('Y')
fig.colorbar(surf, shrink=0.6)
plt.show()

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