Step function returning NaN values.
Información
La pregunta está cerrada. Vuélvala a abrir para editarla o responderla.
Mostrar comentarios más antiguos
T = A(i,1);
K = A(i,2);
if T==0
T=0.001;
end
s = tf('s');
X= ((-1*s^3)+(-1.533*10e-17*s^2)+(0.0001996*s)+9.227*10e-22)/((s^5)+(-2.602*10e-18*s^4)+(0.00378*s^3)+(6.935*10e-21*s^2)+(1.267*10e-6*s));
Y= 0;
Z= ((-0.01994*s^2)+(-3.174*10e-5))/((s^5)+(-2.602*10e-18*s^4)+(0.00378*s^3)+(6.935*10e-21*s^2)+(1.267*10-6*s));
num=[(0.6*(T^2)*K) 4.8*K*T 9.6*K];
den=[8*T 0];
tfPID=tf(num,den);
itf=X+Y+Z;
jtf=itf*tfPID;
ftf=jtf/(1+jtf);
step(ftf);
dt = 20;
t = 0:dt:800;
e = 1 - step(ftf,t);
H = sum(t'.*abs(e)*dt);
My step function, for varying values of T and K, is giving nan values.I made sure that denominator does not become zero. This is affecting my values in H. How to avoid this? Please help.
Respuestas (0)
La pregunta está cerrada.
Productos
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!