How do I solve these differential equations using a while loop?
Mostrar comentarios más antiguos

1 comentario
Roger Stafford
el 11 de Mzo. de 2018
Editada: Roger Stafford
el 11 de Mzo. de 2018
If you want to allow delta t to approach zero as a limit, you can solve these equations using one of the ode functions. The first equation, for example, would have the form:
dU/dt = k1-k2*X./((X.^2+Y.^2+Z.^2).^(3/2))
On the other hand if you wish to solve them using delta t as a fixed nonzero value, then do so with a for-loop to provide the iteration, not a while-loop. Just carry out the operations you have given here within the for-loop at each step going from the n-th values to the n+1-st values.
Respuesta aceptada
Más respuestas (1)
Abraham Boayue
el 12 de Mzo. de 2018
clear variables
close all
% Define parameters
dt = dt;
t = t0:dt:tf;
n = length(t);
m = m;
thx = thx;
thy = thy;
thz = thz;
G = G;
Me = Me;
% Initializations Initial conditions Boundary conditions
u = zeros(1,n); u(1) = u0; u(n) = un;
v = u; v(1) = v0; v (n)= vn;
w = v; w(1) = w0; w(n) = wn;
x = w; x(1) = x0; x(n) = xn;
y = x; y(1) = y0; y(n) = yn;
z = y; z(1) = z0; z(n) = zn;
for i = 2: n-1
u(i+1) = u(i) + (thx/m - G*Me*(x(i)/(x(i)^2 +y(i)^2 +z(i)^2)^(3/2)))*dt;
v(i+1) = v(i) + (thy/m - G*Me*(y(i)/(x(i)^2 +y(i)^2 +z(i)^2)^(3/2)))*dt;
w(i+1) = w(i) + (thz/m - G*Me*(z(i)/(x(i)^2 +y(i)^2 +z(i)^2)^(3/2)))*dt;
x(i) = x(i) + u(i+1)*dt;
y(i) = y(i) + v(i+1)*dt;
z(i) = z(i) + w(i+1)*dt;
end
figure;
plot(t,u,'linewidth',2);
hold on
plot(t,v,'linewidth',2);
plot(t,w,'linewidth',2);
plot(t,x,'linewidth',2);
plot(t,y,'linewidth',2);
plot(t,z,'linewidth',2);
a = ylabel('Pressure');
set(a,'Fontsize',14);
a = xlabel('x');
set(a,'Fontsize',14);
a=title(['Solution to system of ode - dt = ' num2str(dt)]);
legend('u', 'v','w','x','y','z')
xlim([0 1]);
set(a,'Fontsize',16);
grid;
5 comentarios
Abraham Boayue
el 12 de Mzo. de 2018
Hey Christopher Here is a model solution to your equations. I could not test the code since you did not provide any parameter. The coding was straight forward using a for loop as Roger suggested. I hope this will help you get started with your coding. Best of lucks!
Christopher Maraj
el 12 de Mzo. de 2018
Abraham Boayue
el 12 de Mzo. de 2018
Hey Chris, what are these equations by the way? Do you have access to the actual differential equations? Can you post the values of the parameters as well as the initial and boundary conditions? I would like to see what they represent by running the code.
Christopher Maraj
el 12 de Mzo. de 2018
Christopher Maraj
el 12 de Mzo. de 2018
Categorías
Más información sobre Loops and Conditional Statements en Centro de ayuda y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!

