Edge detection using Fuzzy Logic
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I am trying to detect edge of gray scale image using fuzzy logic. In my code first I am trying to detect edge and then to remove noise. Edge detection part is working,but noise removal part have not worked. Edge detection pixels have values between 0 to 50 and background pixel values have constant value i.e. 128. In case of noise removal I put if else conditions . But each checked pixel i.e. z(i,j) satisfies only if condition whether it is true or not. Following is my code.........
a=imread('a.jpg');
g1=rgb2gray(a);
g=imresize(g1,[200 200]);
[m,n]=size(g);
%figure, imshow(g)
%edge detection part
t=readfis('edge.fis');
z=uint8(zeros(m,n));
for i=2:m-1
for j=2:n-1
F = [g(i-1,j-1) g(i-1,j) g(i,j-1) g(i,j)];
h=double(F);
z(i,j)=evalfis(h,t);
end
end
disp(z)
figure, imshow(z)
%noise removal part
z2=uint8(zeros(m,n));
for i=2:m-1
for j=2:n-1
if ((0<=z(i-1,j-1)<=50) & (0<=z(i-1,j)<=50) & (0<=z(i-1,j+1)<=50) & (0<=z(i,j-1)<=50) & (0<=z(i,j)<=50) & (0<=z(i,j+1)<=50) & (0<=z(i+1,j-1)<=50) & (0<=z(i+1,j)<=50) & (0<=z(i+1,j+1)<=50))
% if z1(i-1,j-1)==0 && z1(i-1,j)==0 && z1(i-1,j+1)==0 && z1(i,j-1)==0 && z1(i,j)==0 && z1(i,j+1)==0 && z1(i+1,j-1)==0 && z1(i+1,j)==0 && z1(i+1,j+1)==0
z2(i,j)=128;
else
z2(i,j)=z(i,j);
end
end
end
figure, imshow(z2)
2 comentarios
matlab_image
el 31 de Mayo de 2012
hi Res,
I cant help you but i need ur help. i also want to do edge detection with fuzzy logic. but i don't know how to start. can you please suggest me something for writing fuzzy logic code.
Thanks in advance
Respuestas (3)
Omid Sarrafzadeh
el 30 de Jul. de 2012
Hi Res It depends on your 'edge.fis' FIS and your rules. May I know more about them?
1 comentario
Arkadiy Turevskiy
el 20 de Mzo. de 2014
Please take a look at a new example we added in 14a showing how to do edge detection with Fuzzy Logic .
0 comentarios
hamed Aghapanah
el 4 de Oct. de 2019
Dear Res,
I do it and ind that there are many solution to find edge. Because the result is related to Membership Functions.
which one is the best solution?
thanks
0 comentarios
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