Info
La pregunta está cerrada. Vuélvala a abrir para editarla o responderla.
How to check the accessibility between two points in a matrix?
1 visualización (últimos 30 días)
Mostrar comentarios más antiguos
I have following matrix:
board =
0 0 0 0 0 0 0 2
0 0 0 0 0 0 2 2
0 0 0 0 0 2 2 0
0 0 0 1 2 2 0 0
0 0 1 1 2 0 0 0
0 1 1 1 2 0 0 0
1 1 0 1 2 0 0 0
1 0 0 11 2 22 0 0
I need to check how many zeroes are accessible from 11 & 22 while they can't cross 2 and 1 respectively. And also is there any path between 11 and 22 keeping the same condition in view. Can anybody help?
3 comentarios
Walter Roberson
el 21 de Mzo. de 2018
"how many zeroes are accessible from 11 & 22 while they can't cross 2 and 1 respectively."
So 2 is a barrier for a path that starts from 11, and 1 is a barrier for a path that starts from 22, but 2 is not a barrier for a path that starts from 22 and 1 is not a barrier for a path that starts from 11 ? That would imply that the paths are not symmetric -- that you might be able to get from 11 to 22 but not back, or from 22 to 11 but not back. Indeed, to get from 22 to 11 you could go 22 -> 2 -> 11 because the 2 is not a barrier when starting from 2, but there is no route from 11 to 22 that does not cross the barrier of 2s that applies when starting from 11 ?
Respuestas (1)
thitch
el 21 de Mzo. de 2018
I would recommend implementing a simple region growing algorithm (google it), where your seed points are 11 and 22. You can keep track of each region's progress in separate logical arrays.
This should produce a logical condition for counting the number of zeros within each region. Making some assumptions about your problem, this would also provide a way of identifying the existence of a path between region '11' and region '22', e.g. something like:
% inRegion11, inRegion22 are logical arrays
if nnz(AND(inRegion11,inRegion22))
% path exists
end
1 comentario
Walter Roberson
el 21 de Mzo. de 2018
This is generally a useful technique.
For this particular problem, I think there might be an easier method -- but first I need the poster to clarify about the blocking rules.
La pregunta está cerrada.
Ver también
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!