1D time dependent mass transfer and reaction in a very small slab

I am trying to model a pde including advection-diffusion and reaction terms. i want to see the concentration profil after a long time(2*60*60 sec) in a very tiny slab(5 micrometer). i used method of line(ode15s) to solve this pde but my result is not match with the experimental result. because the outlet concentration gets maximum concetration right away(as can be seen in myplot).does anybody know where is my mistake?

3 comentarios

Torsten
Torsten el 29 de Mzo. de 2018
Editada: Torsten el 29 de Mzo. de 2018
Did you try MATLAB's "pdepe" ?
But if the velocity is 0.5 m/s, I'm no surprised that the outlet concentration reaches its maximum right away.
How can someone know where your mistake might be, if you don't show the code you wrote?
I don't see anything wrong with your pdepe code. So I suspect there is something wrong with your constants (values or units). For example, if I make the total time 1e-7 instead of 120, the solution looks more reasonable.

Iniciar sesión para comentar.

 Respuesta aceptada

By carefully defining the parameters of your function in matlab using the pdepe solver, I was able to obtain the image below. Does this look like what you want to see?
function PDEPE_diff
m = 0;
x = linspace(0,1,200);
t = linspace(0,2,100);
sol = pdepe(m,@pdepfun,@icfun,@bcfun,x,t);
u = sol(:,:,1);
plot(x,u(1:100,:,1),'linewidth',1.5)
title('Numerical solution computed with 200 mesh points.')
xlabel('Distance x')
ylabel('Time t')
grid
function [g,f,s] = pdepfun(x,t,c,DcDx)
D = 8.6e-6;
k = 1;
K = 0.24;
ux = 0.5;
g = 1;
f = D*DcDx;
s = -(ux*DcDx + k*K*c);
function c0 = icfun(x)
c0 = 0*x;
function [pl,ql,pr,qr] = bcfun(xl,cl,xr,cr,t)
pl = cl-20;
ql = 0;
pr = cr;
qr = 1;
%

1 comentario

I understand what you mean. I strongly believe that it depends on the method of coding, you could try other numerical schemes like the finite difference method. Was it mentioned how the results were obtained in the paper that you are reading?

Iniciar sesión para comentar.

Más respuestas (0)

Etiquetas

Preguntada:

el 29 de Mzo. de 2018

Abierta de nuevo:

el 12 de Abr. de 2018

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by