How do I create a scatter plot of every value combination of three vectors?

I have three vectors each corresponding to a position of a seat in a theater. x = [0:60], y = [0:60] and z = [y.*5]. So I have an x vector, a y vector, and a z vector. I need to be able to plot every combination of the vectors because when I use scatter3(x,y,z) it plots x(n), y(n) and z(n), creating a diagonal line of seats. So I also need it to plot x(n), y(n+1), z(n+1).

 Respuesta aceptada

[X, Y, Z] = ndgrid(x, y, z);
scatter3( X(:), Y(:), Z(:));

3 comentarios

[X, Y, Z] = ndgrid(x, y, z);
X = X(:); Y = Y(:); Z = Z(:);
[~, uaidx] = unique(Z);
scatter3( X(uaidx), Y(uaidx), Z(uaidx));
clear; clc;
x = [0:90];
x = [-7:7];
z = 30*tand(12.5)
M = z.*y
amountToAdd = size(x);
L = repmat(M, amountToAdd(2), 1);
for i = [1:length(x)]
for j = [1:length(y)]
d(i,j) = sqrt((x(i)).^2+(y(j)).^2+(z*y(j))^2)
end
end
dB = 10.*log10(1./d.^2)+100;
surf(y,x,L, dB)
This is my current code. I've attached something similar to what I'm looking for but I have it as a surface and I need it as a scatter plot. I think I'm probably just not being clear with what I'm looking for
Try the below and suggest how you want it changed.
x = 0:90;
y = -7:7;
z = 30*tand(12.5);
M = z.*y;
amountToAdd = size(x);
L = repmat(M, amountToAdd(2), 1);
for i = 1:length(x)
for j = 1:length(y)
d(i,j) = sqrt((x(i)).^2+(y(j)).^2+(z*y(j))^2);
end
end
dB = 10.*log10(1./d.^2)+100;
[X, Y] = ndgrid(x, y);
scatter3(Y(:),X(:),L(:),10,dB(:));

Iniciar sesión para comentar.

Más respuestas (2)

Hey Luke,
Have you considered looping through the values of your matrix and plotting for each of the values?
It would go something like this -
% x = 0:4;
y = 0:4;
z = y*5;
q = ones(5,1);
q = q';
for i = 1:length(z)
for j = 1:length(y)
scatter3(x,y(j)*q,z(i)*q)
hold on
end
end
end
Hope this helps!

1 comentario

That is close to what I'm looking for, but I need the z values to only appear once so instead of a cube, I would want it to be a diagonal plane that increases in z values as the y values increase

Iniciar sesión para comentar.

Categorías

Preguntada:

el 6 de Abr. de 2018

Respondida:

el 12 de Abr. de 2018

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by