integration
1 visualización (últimos 30 días)
Mostrar comentarios más antiguos
please can someone help me to solve this problem: I want to integrate this function:
exp(0.5*(1-((l-hm)/(2*H))-exp(-((l-hm)/(2*H)))))
I make this program:
hm=400;
H=50;
syms l;
H0=int(exp(0.5*(1-((l-hm)/(2*H))-exp(-((l-hm)/(2*H))))),l,hm,700)
but the answer is:
100*2^(1/2)*pi^(1/2)*exp(1)^(1/2)*(erf(2^(1/2)/2) - erf(2^(1/2)/(2*exp(3/2))))
how to get the right answer???
0 comentarios
Respuestas (3)
Alexander
el 25 de Mayo de 2012
Why do you think that the answer is incorrect? If you just want a number, use double on the result:
>> double(H0)
ans =
209.1673
Or use INTEGRAL as Mike Hosea suggests.
2 comentarios
Mike Hosea
el 25 de Mayo de 2012
:lol: I didn't even bother with the symbolic attempt and completely misinterpreted the question. I'm blaming this on Walter. :)
Mike Hosea
el 25 de Mayo de 2012
I never quite know what to say when questions like this come up. There's nothing wrong with wanting to do integrals analytically, to be sure, and some times there are legitimate reasons, I guess, but I wonder what people need the analytical answer for. This problem is really no problem for INTEGRAL (or QUADGK)
>> integral(@(l)exp(0.5*(1-((l-hm)/(2*H))-exp(-((l-hm)/(2*H))))),hm,700)
ans =
2.091673274741571e+02
>> 100*2^(1/2)*pi^(1/2)*exp(1)^(1/2)*(erf(2^(1/2)/2) - erf(2^(1/2)/(2*exp(3/2))))
ans =
2.091673274741571e+02
0 comentarios
Walter Roberson
el 25 de Mayo de 2012
MuPAD is not able to complete that integral. (Maple is not able to do it either.)
Perhaps there is an appropriate change of variables, but I have not been able to locate one.
7 comentarios
Christopher Creutzig
el 25 de Mayo de 2012
If it helps to get some confidence in the result: To get integrals.com to integrate the expression (indefinitely), substitute x=exp(-l/200). http://integrals.wolfram.com/index.jsp?expr=-200*exp%285%2F2+-+%281%2F2%29*x^2*exp%284%29%29&random=false
Ver también
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!