Copying dynamic array to MxArray object using memcpy in c++

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ShimShim
ShimShim el 10 de Abr. de 2018
Comentada: ShimShim el 17 de Abr. de 2018
Hi I am trying to copy a n*m matrix defined by dynamic memory allocation to mxArray, and send it to matlab the matrix is sent right in size but false in values. I appreciate if anyone can help me to find what is wrong. here is the code
double **dataDMA;
int m = 3, n = 3, c = 0;
mxArray *matDDMA;
dataDMA = (double **)calloc(sizeof(double *), m); // number of columns
for (int i = 0; i < m; ++i)
{
dataDMA[i] = (double *)calloc(sizeof(double), n); // number of rows
}
printf("\nMatrix created by Dynamic Memory Allocation:\n");
for (int i = 0; i < n; i++)
{
for (int j = 0; j < m; j++)
{
dataDMA[i][j] = c+1;
printf("%g ", dataDMA[i][j]);
c = c + 1;
}
printf("\n");
}
matDDMA=mxCreateDoubleMatrix(m, n, mxREAL);
if (matDDMA == NULL)
{
printf("Unable to create mxArray matDDMA.\n");
return(EXIT_FAILURE);
}
memcpy((void *)mxGetPr(matDDMA), (void *)dataDMA, m*n *sizeof(double));
engPutVariable(ep, "matDDMA", matDDMA);
engEvalString(ep, "matDDMA");

Respuesta aceptada

James Tursa
James Tursa el 11 de Abr. de 2018
Editada: James Tursa el 11 de Abr. de 2018
Two fundamental problems:
1) You can't guarantee that successive calls to calloc( ) will produce memory segments that are adjacent to each other in memory. So the entire concept of using a single memcpy to copy such memory as one big block is non-conforming. If might happen to work if you are lucky, and then the next time the program will bomb because you weren't lucky. If you want to copy it all as one single block of memory, then you need to allocate it as such. E.g.,
dataDMA = (double **)calloc(sizeof(double *), m); // number of columns
dataDMA[0] = (double *)calloc(sizeof(double), n*m); // entire block of double memory
for (int i = 1; i < m; ++i) // <-- start loop indexing at 1
{
dataDMA[i] = dataDMA[i-1] + n; // next column is n elements over
}
Then, when you are done with this memory you only have two free( ) calls to make:
free(dataDMA[0]);
free(dataDMA);
2) The dataDMA pointer points to the column address array, not to the double data itself. So your memcpy source address is wrong. It should be this:
memcpy(mxGetPr(matDDMA), dataDMA[0], m*n *sizeof(double)); // don't need (void *) here
  6 comentarios
James Tursa
James Tursa el 17 de Abr. de 2018
Does the first value scan in correctly? I would work on just getting this first number to work properly, and then move on to the rest of the file.
ShimShim
ShimShim el 17 de Abr. de 2018
James, I changed all doubles to float, also used mxArray* matdata1DMA = mxCreateNumericMatrix(mm, nn, mxSINGLE_CLASS, mxREAL); instead of mxArray* matdata1DMA = mxCreateNumericMatrix(mm, nn, mxREAL); which worked.
The only matter was with the image which was flipped, so I changed the indexes in the for loop to data1DMA[i][j] to data1DMA[j][i] when scanning as below;
for (int i = 0; i < mm; i++)
{
for (int j = 0; j < nn; j++)
{
fscanf(input_file, "%f ",&data1DMA[j][i]);
}
}
Thanks a lot for your help.

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