Regsrding for loop with array

Hi all, A=[1;3;5; 6]; for 1 to 100 iterations, if any element in array matches with the iteration,e.g .for 1st iteration A's 1st data is matching. else it should come out from the loop. Can u suggest me any idea?

Thanks

[Muruganandham Subramanian]

for lm=1:100

if (~isempty(find(A == lm)))

%calcultion

end

end

Answer 1

[Wayne King]

   for nn = 1:8 
   if(any(A==nn)), 
   disp('hi');
   else 
   disp('bye'); 
   end
   end

Obviously, replace disp('hi') with your calculation and I've just shown this up to an index of 8.

Answer 2

[Muruganandham Subramanian]

Hi wayne, This also works!!! for lm=1:100 if (~isempty(find(A == lm))) %calcultion end end

[Wayne King]

Hi, sorry! I didn't see your comment above :)