Good afternoon, I'm quite a newbie in MatLab, and I'm trying to use the fminsearch function to fit both a normal and a sigmoidal/logistic models to my data. At the moment, I'm using the following formula for the logistic: [par fit]=fminsearch(@(p) norm(1./(1+exp(-p(1).*(X-p(2)))) -Y), [1,1]);
X corrisponds to 10 different location of a stimulus, while Y is the answer (0/1) given to the stimulus. However, the outcomes I obtain in this way seem totally untrustworthy, even if the formula is the correct logistic formula. There is something I'm missing?
Thank you in advance, Alessandro

 Respuesta aceptada

Star Strider
Star Strider el 19 de Abr. de 2018

0 votos

When in doubt, simulate:

p = [2 5];
X = 0:20;
Yfcn = @(p,X) 1./(1+exp(-p(1).*(X-p(2))));
Y = Yfcn(p,X) + 0.1*randn(size(X));
[par fit]=fminsearch(@(p) norm(1./(1+exp(-p(1).*(X-p(2)))) -Y), [1,1])
figure(1)
plot(X, Y, 'p')
hold on
plot(X, Yfcn(par,X), '-r')
hold off
grid

It looks good to me, and the parameter estimates are appropriate. If you are not getting reasonable results, experiment with different initial parameter estimates.

Más respuestas (3)

Alessandro Zanini
Alessandro Zanini el 19 de Abr. de 2018

0 votos

Thank you so much! The simulation runs perfectly, so I think I have problems with the X: probably only 10 positions are insufficient for the sigmoid

1 comentario

Star Strider
Star Strider el 19 de Abr. de 2018
As always, my pleasure!
You have only 2 parameters, so 10 data points should be enough to provide good parameter estimates. The fminsearch algorithm is derivative-free, although it still requires initial parameter estimates that are reasonably close to the optimal estimates. I would continue to vary the initial estimates across a wide range of values to see if you can get a good fit. The initial estimate for ‘p(1)’ can be any positive value. An appropriate initial estimate for ‘p(2)’ would be mean(X).

Iniciar sesión para comentar.

Alessandro Zanini
Alessandro Zanini el 19 de Abr. de 2018

0 votos

Correct. Modifying the parameters the curve fits without problems, even in 10 positions. Thanks!
Jeff Miller
Jeff Miller el 20 de Abr. de 2018
Editada: Jeff Miller el 20 de Abr. de 2018

0 votos

Alessandro, it sounds like you are fitting probit models and/or psychometric functions. If so, you might find some very useful routines here: Cupid . DemoProbit.m shows some examples of how you could fit such models with various underlying distributions (normal, logistic, etc).

3 comentarios

Alessandro Zanini
Alessandro Zanini el 20 de Abr. de 2018
Thanks! But the link leads to a "not existing" page
Jeff Miller
Jeff Miller el 20 de Abr. de 2018
Sorry, here is the link in plain text: https://github.com/milleratotago/Cupid
Alessandro Zanini
Alessandro Zanini el 20 de Abr. de 2018
Thanks again!

Iniciar sesión para comentar.

Categorías

Más información sobre Get Started with Curve Fitting Toolbox en Centro de ayuda y File Exchange.

Preguntada:

el 19 de Abr. de 2018

Editada:

el 20 de Abr. de 2018

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by