Increase determine step size

Hello I want to have this steps (1,2,4,6,8).

How can I do it to be in the form of, for example:

n=5 
n=1:2:((2*n)-2)

Answer 1

[Walter Roberson]

t = 1:5; steps = 3+(-53/12+(71/24+(-7/12+(1/24)*t).*t).*t).*t

I would suggest that you reconsider your task. It would, for example, have been much easier as

t = 1:5; steps = [1, (t(2:end)-1)*2]

[Kostas Tsakos]

I want the code to be x=1:times 2:8 (so i get 1,2,4,6,8)

[Walter Roberson]

You cannot get that.

You can use (t-1)*2 + (t==1) or other ways of making an exception for the first value, but the 1 entry cannot be handled with a plain increment.

Now, if you had wanted [1, 2, 4, 8] without the 6 then that would have been easy: t = 1:4; 2.^(t-1)

Answer 2

[Image Analyst]

Try this:

n = 5;
n = [1,2:2:((2*n)-2)]

n = 1×5

1 2 4 6 8