Borrar filtros
Borrar filtros

dsolve problem

2 visualizaciones (últimos 30 días)
Daniel
Daniel el 31 de Mayo de 2012
Hello, I would like to use a function f in a differential equation for example f=x but get a crazy result.
syms x y f
f=x
y=dsolve('D2x=-f','x(0)=1','Dx(0)=0')
How can I put into dsolve a function f defined outside of dsolve?

Respuesta aceptada

Teja Muppirala
Teja Muppirala el 1 de Jun. de 2012
One way would be to convert f to a string:
syms x y f
f=x
y=dsolve(['D2x=-' char(f)],'x(0)=1','Dx(0)=0')
  1 comentario
Daniel
Daniel el 1 de Jun. de 2012
Thank you Teja!

Iniciar sesión para comentar.

Más respuestas (1)

Walter Roberson
Walter Roberson el 31 de Mayo de 2012
You could try
syms x y f
f=x
eqn1 = subs(sym('D2x=-f'), 'f', f);
y = dsolve(eqn1, 'x(0)=1','Dx(0)=0')
  3 comentarios
Walter Roberson
Walter Roberson el 31 de Mayo de 2012
Ah, I guess it doesn't analyze syms for occurrences of D. Ummm, I will have to make up a variable for x to be related to:
If I read the documentation right,
syms x(t) f(t) t
f = x(t); %or maybe f = x;
D2x = diff(x,2);
Dx = diff(x);
dsolve( D2x == -f, x(0) == 1, Dx(0) == 0 )
Anyhow, the root of the problem is that, as usual, when you have a quoted string like 'D2x=-f', MuPAD does not have access to the value of any variable such as f that was declared at the MATLAB level. subs() is the mechanism to "import" MATLAB-level values to the MuPAD level. It looks like dsolve() interprets symbolic variables differently than it interprets strings so the more obvious subs() does not work. char() around the subs() might perhaps have worked.
Daniel
Daniel el 1 de Jun. de 2012
Thanks for trying.
Teja's code works:
syms x y f
f=x
y=dsolve(['D2x=-' char(f)],'x(0)=1','Dx(0)=0')

Iniciar sesión para comentar.

Etiquetas

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by