How to plot circle by one single equation?

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Ameer Hamza
Ameer Hamza el 13 de Mayo de 2018
Comentada: krishan Gopal el 9 de Dic. de 2021
I need code which plot the circle in one single equation (variable). I have the code but i need code of single equation, the code which i have, it is composed of two equations as follow :
r=2;
x=0;
y=0;
th = 0:pi/6:2*pi;
xunit = r * cos(th) + x;
yunit = r * sin(th) + y;
plot(xunit, yunit);

Respuesta aceptada

John D'Errico
John D'Errico el 13 de Mayo de 2018
Editada: John D'Errico el 13 de Mayo de 2018
As one "equation" what does that mean? About the best I can offer is this:
r=2;
x0=0;
y0=0;
ezplot(@(x,y) (x-x0).^2 + (y-y0).^2 -r^2)
axis equal
Be careful that the units are equal for the two axes, else it ill not look circular.
I could also have done it using fimplicit.
r=2;
x0=0;
y0=0;
syms x y
fimplicit((x-x0).^2 + (y-y0).^2 -r^2)
axis equal
So, in either case, only one equation.
If you really insist on only one "variable, then you need to use a polar coordinate transformation. Thus, you can do it in terms of polar angle theta, as:
r=2;
x0=0;
y0=0;
theta = linspace(0,2*pi,100);
plot(x0 + r*cos(theta),y0 + r*sin(theta),'-')
axis equal
So only one variable, theta. If you are hoping for something else, something more or less, then you need to explain carefully what the goal is here.
Are you looking for a simple way to plot a circle? Perhaps try this:
cplot = @(r,x0,y0) plot(x0 + r*cos(linspace(0,2*pi)),y0 + r*sin(linspace(0,2*pi)),'-')
Now you have a little function that will plot a circle.
cplot(2,0,0)
hold on
cplot(3,1,2)
cplot(1,-1,1)
axis equal
  2 comentarios
Abdulrahman Saad
Abdulrahman Saad el 5 de Oct. de 2019
Thank you very much
krishan Gopal
krishan Gopal el 9 de Dic. de 2021
Hi, can you tell me how to draw line pattern inside the circle

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Más respuestas (3)

Aditya Gupta
Aditya Gupta el 26 de Jun. de 2020
Adding to the MVP's (perfect) answer, I found one more way:
radius = 2;
originX = 0;
originY = 0;
rectangle('Position',[originX-radius originY-radius 2*radius 2*radius], ...
'Curvature',[1 1]);
axis equal

Harshith pothuri
Harshith pothuri el 14 de En. de 2021
r=2;
x0=0;
y0=0;
theta = linspace(0,2*pi,100);
plot(x0 + r*cos(theta),y0 + r*sin(theta),'-')
axis equal

krishan Gopal
krishan Gopal el 9 de Dic. de 2021
Hi, can you tell me how to draw line pattern inside the circle

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