How to make image array with X,Y coordinates and displacement?

2 visualizaciones (últimos 30 días)
Hi guys. I need some help.
I have 5883 x 5 matrix data. it was made by Abaqus (Finite Element method) program. first column is just node number. second column is X coordinate, third column is Y coordinate, fourth column is Z coordinate, fifth column is displacement.
I just want to make 256 * 256 matrix from this data for visualizing and processing with imagesc. (I just want 2D image (X,Y and displacement only))
You can check this data with this code.
figure;scatter3(centerSlice(:,2),centerSlice(:,3),centerSlice(:,4),100,centerSlice(:,5),'.');
please help. thanks.

Respuesta aceptada

KSSV
KSSV el 21 de Mayo de 2018
If you have nodal connectivity data and coordinates, displacement data in hand, you can use the following file-exchange.
  18 comentarios
KSSV
KSSV el 23 de Mayo de 2018
YOu can make your mesh like this:
N = 50 ;
R0 = 0.04 ; R1 = 0.08 ;
th = linspace(0,2*pi,N) ;
R = linspace(R0,R1,N) ;
[R,th] = meshgrid(R,th) ;
X = R.*cos(th) ;
Y = R.*sin(th) ;
Z = zeros(size(X)) ;
surf(X,Y,Z)
You need to interpolate your displacement data with these X,Y so, that you can use surf and get the plot you want.
Jae-Won Yoo
Jae-Won Yoo el 23 de Mayo de 2018
okay.. Thank you for your answer and attention. I learned many things.
Good luck and have a nice day.

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