cart2pol angle sin 0 to 2pi range instead of -pi to pi range?

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I have a huge set of x and y coordinates that I have converted to polar coordinates using cart2pol, but I need to have my range of angles to be 0 to 2pi instead of -pi to pi. How can I do this without manually adding 2pi to each negative theta?

Respuestas (2)

John D'Errico
John D'Errico el 24 de Oct. de 2018
The most efficient solution is to use mod. Thus...
theta = mod(cart2pol(x,y),2*pi);
This works, because what you really want is to add 2*pi to the angle, whenever the angle is less than zero. mod does exactly that. And, yes, mod works for non-integer moduli, and of course mod is vectorized, so it does everything you need without even a need for a loop.

theodore panagos
theodore panagos el 7 de Nov. de 2018
You can use the formula:
atan(x,y)=pi()-pi()/2*(1+sign(x))*(1-sign(y^2))-pi()/4*(2+sign(x))*sign(y)
-sign(x*y)*atan((abs(x)-abs(y))/(abs(x)+abs(y)))
there is x=x2-x1 and y=y2-y1
The formula give the angle from 0 to2pi for all the values x and y
For x=y=0 the result is undefined.

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