Help reducing memory usage during large matrix multiplication
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I have a certain 343-by-343 matrix V3 and a certain 343-by-1 vector V2 produced by certain algorithm and I want to do the following operation:
V4 = V3*(V2-I*C)
where I = eye(343), and C is a vector of zeros except for the 172th element, which is 1. I provided V3 and V2 as a workspace file in attachment. The size for V2 is actually big despite only having 343 elements because the elements contain symbols (namely "t") and a lot numbers. But the lengthy values of these elements are crucial.
The problem is, the memory usage during the calculation is about 14.5 GB (out of 15.284 GB available), and the calculation is quite slow. Since I am planning to do much larger scale calculations, this is very problematic to me.
Is there any workaround to prevent using so much RAM? Or is there nothing I can do other than to expand the RAM?
2 comentarios
KSSV
el 29 de Mayo de 2018
Why don't you, substitute value of t, convert it to double and then multiply?
Respuestas (1)
Sergey Kasyanov
el 9 de Jun. de 2018
Editada: Sergey Kasyanov
el 9 de Jun. de 2018
I think that problem can be solved by the manual multiplication of matrices.
%note: V2=(V2-I*C) is the same V2(172)=V2(172)-1;
V2(172)=V2(172)-1;
A=vpa(zeros(length(V2),1));
V2=V2.';
for i=1:length(V2)
A(i)=sum(V3(i,:).*V2);
end
A is the answer.
1 comentario
Sergey Kasyanov
el 9 de Jun. de 2018
Also you may use that solution. It claims less memory but It has less accuracy due to convertion integer ratio coefficients to float .
V2(172)=V2(172)-1;
A=vpa(zeros(length(V2),1));
V2=vpa(V2.');
for i=1:length(V2)
A(i)=sum(V3(i,:).*V2);
end
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