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Matrix indexing of a 3D matrix, one by one each 3D layer?

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JAI PRAKASH
JAI PRAKASH el 12 de Jul. de 2018
Respondida: Rik el 12 de Jul. de 2018
J = cat(3, magic(4), magic(4), magic(4)); % 3D matrix
maskIdx = J(:,:,1)>8;
%%I want to do something like below
J{:,:,1}(maskIdx) = ones(8,1);
J{:,:,2}(maskIdx) = 2*ones(8,1);
J{:,:,3}(maskIdx) = 3*ones(8,1);
Please focus on LHS only. How to apply same maskIdx on different layers. Note maskIdx created by the 1st layer which is 2D.
  2 comentarios
Rik
Rik el 12 de Jul. de 2018
The only thing I can think of is using find and subs2ind to generalize this, but that feels very ineffective. So if nobody has a better idea and you can't implement this on your own, comment here and I'll post an answer with example code.
JAI PRAKASH
JAI PRAKASH el 12 de Jul. de 2018
Editada: JAI PRAKASH el 12 de Jul. de 2018
i understood ur idea.
I am looking if, it can be done in a miraculous way!! (I mean most efficient way)
Because if suppose J is a very big(10000x10000x3), then maskIdx will be 3 times. That's why I want to avoid the repetition.

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Rik
Rik el 12 de Jul. de 2018
Logicals are 8 times smaller than doubles, so memory concerns shouldn't be an issue. If you can work with a big J, you can easily afford to replicate the mask. The code below does its thing in 3.4 seconds for a 1000000x100x3 J.
1e5 done in 0.0 seconds
1e6 done in 0.0 seconds
1e7 done in 0.3 seconds
1e8 done in 3.4 seconds
Name Size Bytes Class Attributes
J 1000000x100x3 2400000000 double
maskIdx 1000000x100x3 300000000 logical
code:
for k_base=5:8
k=10^(k_base-2);
clear J maskIdx n targetDim
J=rand(k,100,3);
maskIdx=J(:,:,1)>0.8;
n=sum(maskIdx(:));
A=ones(n,1);
B=2*A;
C=3*A;
tic
maskIdx(1,1,size(J,3))=false;%extend to 3D
targetDim=1;
J(circshift(maskIdx,targetDim-1,3))=A;
targetDim=2;
J(circshift(maskIdx,targetDim-1,3))=B;
targetDim=3;
J(circshift(maskIdx,targetDim-1,3))=C;
fprintf('1e%d done in %.1f seconds\n',log10(numel(J)/3),toc)
end

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