How to convert a matrix to a structure array?
112 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
Hannah
el 18 de Jul. de 2018
Comentada: Hannah
el 19 de Jul. de 2018
I am working with data that is in a matrix but would like to easily convert it to a structure array. At the moment I am using the "table" and "table2struct" commands as per the simple example below but I feel that there should be a more efficient method that I'm missing as I will likely have far more than three variables and the current method I'm using seems inefficient. Any assistance would be appreciated!
M=randn(5,3);
T=table(M(:,1),M(:,2),M(:,3),'VariableNames',{'Var1' 'Var2' 'Var3'});
S=table2struct(T);
2 comentarios
Steven Lord
el 18 de Jul. de 2018
Why do you need to convert the matrix into a struct array? How are you planning to use the fields in the struct later in your code?
Personally most of the time I'd just leave it as M and use indexing to extract the columns as I need them.
Respuesta aceptada
Guillaume
el 19 de Jul. de 2018
I'm with Steven, it would make more sense to keep it as is, or if the columns indeed represent different things, to change it to a table. A simpler version of your conversion would be:
T = array2table(M, 'VariableNames', compose('Var%d', 1:size(M, 2)))
tables are a lot more flexible than structures as you can access data by row or by column. With a structure you're putting the emphasis on the columns at the expense of rows.
If you really want a structure, then, for a matrix with an arbitrary number of column:
S = cell2struct(num2cell(M, 1), compose('Var%d', 1:size(M, 2)), 2)
Más respuestas (0)
Ver también
Categorías
Más información sobre Structures en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!