Info
La pregunta está cerrada. Vuélvala a abrir para editarla o responderla.
Could anyone help me with the following code
1 visualización (últimos 30 días)
Mostrar comentarios más antiguos
code:
user=[2 4 ];
R=[2 3]
Xmax=1
Ymax=1
for t = 1:length(user)
for i = 1:length(R)
radius = R(i)
xsd=ones(1,user(t))*Xmax
ysd=ones(1,user(t))*Ymax
rrx=radius*sqrt(rand(1,user(t)))
thetarx=2*pi*rand(1,user(t))
xrx=xsd+rrx.*cos(thetarx)
yrx=ysd+rrx.*sin(thetarx)
th = 0:pi/100:2*pi
xunit = radius * cos(th) + Xmax
yunit = radius * sin(th) + Ymax
figure
plot(xunit, yunit)
hold on
plot(ysd,xsd,'r^')
hold on
plot(yrx,xrx,'ko')
hold on
end
end
I want to have the graph for 2 user with respect to R=[2 3] on the same figure such that the 2 users should be scatterd.Similarly for 4 user with respect to R=[2 3] on the same figure such that the 4 users should be scatterd.Could anyone please help me on this.
0 comentarios
Respuestas (2)
Adam Danz
el 23 de Jul. de 2018
Editada: Adam Danz
el 23 de Jul. de 2018
The template below will create a figure for each t-user and on each figure will be plotted all Rs for each t_th user.
for t = 1:length(user)
figure
axis
hold on
for i = 1:length(R)
plot()
end
end
This second template will create only 1 figure and all data will be plotted on the same axis.
figure
axis
hold on
for t = 1:length(user)
for i = 1:length(R)
plot()
end
end
Did that answer your question?
9 comentarios
Adam Danz
el 24 de Jul. de 2018
Prabha, I don't understand what you need. Please describe each figure or draw a picture and upload it.
Tell me what's wrong here:
- you want two figures
- In figure 1, there will be data from 2 users (4 data points).
- In figure 2, there will be data from 4 users (8 data points).
- In figure 1, there should be two circles.
- In figure 2, there should also be two circles.
More importantly, is this your code or are you trying to adapt someone else's code? Have you tried stepping through the code in debug mode to understand what the problem is? Please reply to those questions first before I can help you more.
Ver también
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!