Setting up a while loop

For an introduction to MATLAB, Ive been working on the following problem, however i keep getting the anwser for a_n and b_n as 0
my code is as follows;
n = 0
fprintf('a_n | b_n\n')
a_n = (6/sqrt(3))*((-1)^n/(3^n(2*n+1)));
b_n = 16*((-1)^n/5^(2*n+1)*(2*n+1))-4*((-1)^n/239^(2^n+1)*(2*n+1));
a_n_Error = abs(a_n - pi);
b_n_Error = abs(b_n - pi);
tol = 1e-6;
while a_n_Error >= tol && b_n_Error >= tol
n = n+1;
a_n = (6/sqrt(3))*((-1^n)/(3^n)*(2*n+1));
b_n = 16*((-1^n)/(5^(2*n+1))*(2*n+1)) - 4*((-1^n)/(239^(2^n+1))*(2*n+1));
a_n_Error = abs(a_n - pi);
b_n_Error = abs(b_n - pi);
fprintf('%10.6f | %10.6f\n', a_n, b_n)
end

1 comentario

Geoff Hayes
Geoff Hayes el 23 de Jul. de 2018
Zain - the equations in the attached pdf indicate that you should be adding/summing the a_n from the current iteration with the a_n from the previous iteration
a_n = a_n + (6/sqrt(3))*((-1^n)/(3^n)*(2*n+1));
Same for b_n. You will also need to be careful with the order of operations and your placement of the brackets. Please confirm if the above is actually is how described in the pdf.

Iniciar sesión para comentar.

Respuestas (0)

Categorías

Más información sobre Loops and Conditional Statements en Centro de ayuda y File Exchange.

Preguntada:

el 23 de Jul. de 2018

Comentada:

el 23 de Jul. de 2018

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by