How to add text over my bar chart?

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TRISHITA BANERJEE
TRISHITA BANERJEE el 25 de Jul. de 2018
Comentada: Aarti Dwivedi el 26 de Jul. de 2018
I need to add text corresponding to the y axis in my current code..what extra should I add there?
fs = 48000;
L1 = 0.1 * fs;
L2 = 0.01 * fs;
K = 5;
w1 = 50 / fs;
w2 = 20e3 / fs;
c = log(w2/w1);
T = 1.5 * fs;
N = 5;
T_i = zeros(1,N);
ti_K = zeros(1,N);
T_MESM = zeros(1,N);
for n = 1:N
T_i(n) = ((n-1)*L1 + L2) * c/log(2); % sweep length for interleaving n sweeps
if T_i(n) < T
T_i(n) = T;
end
ti_K(n) = T_i(n)/c * log(K); % distance of IR to kth HIR
T_MESM(n) = T_i(n) + ti_K(n)*(N/n-1) + N*L1;
end
t_MESM = T_MESM/fs;
t_i = T_i / fs;
% optimal n
n_opt = ceil( (T*log(2))/(c*L1) + (L1+L2)/L1 );
figure;
for k = 1:N
bar(k,T_MESM(k)/fs);
hold on;
end
hold off; %grid on;
figure;
for k = 1:N
bar(k,T_i(k)/fs);
hold on;
end
hold off; %grid on;
rel_T = T_i(n_opt) / T;
rel_n = (1 + log(K)/c*(N/(n_opt-1)-1)) / (1 + log(K)/c*(N/n_opt-1));
  2 comentarios
TRISHITA BANERJEE
TRISHITA BANERJEE el 25 de Jul. de 2018
Found a solution to my answer:
clear all close all
fs = 48000; % fstart = 55;%55; % fend = fs/2;%24100; %Possible values 20k and 24k % A = 0.04;%0.025; for 0.6m%0.6;%for 1m distance%0.7;%for1.5m % % L1 = 9350; % for -70 db % L2 = 2250; % W1=2*pi*f_start/fs; % W2=2*pi*f_end/fs; L1 = 0.1 * fs; L2 = 0.01 * fs; K = 5; w1 = 50 / fs; w2 = 20e3 / fs; c = log(w2/w1); T = 1.5 * fs; N = 5;
T_i = zeros(1,N); ti_K = zeros(1,N); T_MESM = zeros(1,N);
for n = 1:N T_i(n) = ((n-1)*L1 + L2) * c/log(2); % sweep length for interleaving n sweeps if T_i(n) < T T_i(n) = T; end ti_K(n) = T_i(n)/c * log(K); % distance of IR to kth HIR
T_MESM(n) = T_i(n) + ti_K(n)*(N/n-1) + N*L1;
end
t_MESM = T_MESM/fs;
t_i = T_i / fs;
% optimal n n_opt = ceil( (T*log(2))/(c*L1) + (L1+L2)/L1 );
figure; for k = 1:N y=T_MESM(k)/fs; bar(k,y); for i=1:numel(y) text(k(i),y(i),num2str(y(i),'%0.2f'),... 'HorizontalAlignment','center',... 'VerticalAlignment','bottom') end hold on; end hold off; %grid on;
figure; for k = 1:N y=T_i(k)/fs; bar(k,T_i(k)/fs); for i=1:numel(y) text(k(i),y(i),num2str(y(i),'%0.2f'),... 'HorizontalAlignment','center',... 'VerticalAlignment','bottom') end hold on; end hold off; %grid on;
% n = 4; % %%%%% Equation (14) from Paper %%%%% % b0 = L1 * (c-log(K)); % b1 = (L2-L1)/(c-log(K)) + N*L1*log(2*K); % b2 = (L2+L1) * N * log(K); % % T_paper = 1/log(2) * (b0*n + b1 + b2/n); % T_paper = T_paper / fs % % %%%%% My Equation %%%%% % a0 = L1 * (c-log(K)); % a1 = (L2-L1)*(c-log(K)) + N*L1*log(2*K); % a2 = N * log(K) * (L2-L1); % % T_paddy = 1/log(2) * (a0*n + a1 + a2/n); % T_paddy = T_paddy / fs
rel_T = T_i(n_opt) / T; rel_n = (1 + log(K)/c*(N/(n_opt-1)-1)) / (1 + log(K)/c*(N/n_opt-1));
Aarti Dwivedi
Aarti Dwivedi el 26 de Jul. de 2018
Please put your solution as an answer.

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