Unable to read data with .clv extension

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Mar
Mar el 26 de Jul. de 2018
Comentada: KALYAN ACHARJYA el 30 de Jul. de 2018
Hi,
I am trying to import multiple csv files into Matlab (.csv extension) but I am keep getting an empty structure.
Following online suggestions I used the following line of code:
d = dir('/Users/file_*.clv');
images = arrayfun(@(f) csvread(f.name), dircontent, 'UniformOutput', false);
image = cat(3, images{:});
For some reason seems like Matlab doesn't read the data. I got the following when I checked the size(image). I was expecting a 3D array instead.
ans =
0 0
Below the code I used with the .csv extension:
d = dir('/Users/file_*.csv');
images = arrayfun(@(f) csvread(f.name), dircontent, 'UniformOutput', false);
image = cat(3, images{:});
I got the following error:
>> mult_csv
Error using csvread (line 35)
File not found.
Error in mult_csv>@(f)csvread(f.name)
Error in mult_csv (line 8)
images = arrayfun(@(f) csvread(f.name), dircontent, 'UniformOutput', false);
Any ideas?
P.S. I attached an example of my csv files.
  5 comentarios
Mar
Mar el 26 de Jul. de 2018
I've edited my post to make things more clear. I also attached a file as requested.
Guillaume
Guillaume el 26 de Jul. de 2018
Oh, so this is just a continuation of import-multiple-csv-files-in-matlab.
For some reason, I missed that you commented there (There was a problem yesterday where the activity feed stopped updating for a few hours). I've now updated my answer.

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Respuestas (1)

KALYAN ACHARJYA
KALYAN ACHARJYA el 26 de Jul. de 2018
Editada: KALYAN ACHARJYA el 30 de Jul. de 2018
% Please save all files name in symmetrically before doing the operation
%keep in all one folder, so you avoid the confusion with others files
% names for example f1,f2,f3...
%Save the folder of files in the current directory
path_directory='folder_name_here';
% Pls note the format of files,change it as required
original_files=dir([path_directory '/*.file_extention_format']);
for k=1:length(original_files)
filename=[path_directory '/' original_files(k).csv];
file(k)=csvread (filename);
% Next do your operation and finding
end
  3 comentarios
Guillaume
Guillaume el 26 de Jul. de 2018
Note that if the files are csv files, xlsread is the slowest possible way to read these files. csvread would be much faster.
KALYAN ACHARJYA
KALYAN ACHARJYA el 30 de Jul. de 2018
Thanks @Guillaume

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