Inverse Fourier Transformation with a function in the exponent

2 visualizaciones (últimos 30 días)
Shoaibur Rahman
Shoaibur Rahman el 1 de Ag. de 2018
Editada: Shoaibur Rahman el 1 de Ag. de 2018
I have a signal x[n] with it's Fourier Transform X[k]. I want a frequency-warped signal (x_warp[n]) by taking the inverse Fourier of X[k], with a warping function fun. I know the fun will be somehow incorporated to the exponent of original inverse Fourier e^(j*2*pi*k*n/N)
So far, I have the following code:
x_hat = 1/N * X(1:N/2+1) * exp(1j*fun'/Fs*2*pi*(0:N-1))
x_warp = 2*real(x_hat)
Fs=Sampling frequency. Could you please tell me if the expression in the exponent is correct or not? I.E. what will be exp(???) in the above code?
Thanks in advance!

Respuestas (0)

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by