Can anybody help me to solve this?
4 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
ASWATHI V
el 15 de Ag. de 2018
When I am running this code it shows this error
Undefined function 'times' for input arguments of type 'function_handle'.
Error in withoutpt_fd1 (line 41)
A2 = 1-(a2_1.*a2_5);
a2_1 = lamda_su1*lamda_u1p*(phi_1*k*I)/(p_smax*lamda_u1u2);
a2_2 = @(z) exp((-lamda_u1p-((sig_2.*lamda_u1u2)/(k.*I))).*z);
a2_3 = @(z) z+((lamda_su1.*phi_1.*k.*I)./(p_smax.*lamda_u1u2));
a2_4 = @(z) a2_2(z).*a2_3(z);
a2_5 = @(z) integral(a2_4,0,Inf);
A2 = 1-(a2_1.*a2_5);
0 comentarios
Respuesta aceptada
ADragon
el 15 de Ag. de 2018
Hi ASWATHI, when you call an anonymous function, you need to provide inputs just like a .m function. So, assignment A2 and a2_5 should be written as
a2_5 = @(z) integral(a2_4(z),0,Inf);
A2 = 1 - (a2-1(<z input>).*a2_5(<z input>));
You will need to replace "<z input>" with a numeric value or variable with a numeric values. Hope this helps
AD
4 comentarios
ADragon
el 15 de Ag. de 2018
I'm sorry. I see what you are doing... you are integrating a2_5 for z=0 to Inf. Modify a2_5 to the code below. a2_5 is not a function of z after you integrate. Everything else looks ok.
a2_5 = integral(a2_4,0,Inf);
The result should be the same as the solution provided by Star Strider.
Más respuestas (0)
Ver también
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!