How to run a for loop n times with a different size matrix inside the loop
1 visualización (últimos 30 días)
Mostrar comentarios más antiguos
BryanE
el 5 de Sept. de 2018
I am attempting to run the four values of x_o and y_o through the loop to do conformal mapping. The matrix size of the circle in the loop is different, but I need to run it four times, with four different output graphs. Is this possible in MATLAB? Thanks
Here is what I have so far:
x_o = [0.1, 0.15, 0.2, 0.25]; y_o = [0.1, 0.15, 0.2, 0.25]; n = length(x_o);
for i = 1:n
R = 1;
theta = linspace(0,2*pi,100);
x = R*cos(theta) - x_o;
y = R*sin(theta) + y_o;
b = sqrt(R^2 - y_o.^2) + x_o;
A = x + [(x.*b.^2)./(x.^2 + y.^2)];
B = y - [(y.*b.^2)./(x.^2 + y.^2)];
figure
plot(x,y,'--',A,B)
grid on
end
3 comentarios
Stephen23
el 5 de Sept. de 2018
"My problem is that the matrix don't agree"
Don't agree with what?
Please given an actual example of the inputs and outputs that you expect to get.
Respuesta aceptada
Koundinya
el 10 de Sept. de 2018
Editada: Koundinya
el 11 de Sept. de 2018
You must be getting the error ' Matrix dimensions must agree ', this is because
theta = linspace(0,2*pi,100);
creates a vector theta with dimensions 1x100, R*cos(theta) and R*sin(theta) will also have dimensions equal to 1x100 , but your vector x_o is of dimension 1x4, so adding/subtracting vectors of unequal dimensions will result in an error
% Error occurs at these lines
x = R*cos(theta) - x_o;
y = R*sin(theta) + y_o;
b = sqrt(R^2 - y_o.^2) + x_o;
to iterate through each element of the vectors x_o and y_o, change it to
x = R*cos(theta) - x_o(i);
y = R*sin(theta) + y_o(i);
b = sqrt(R^2 - y_o(i).^2) + x_o(i);
0 comentarios
Más respuestas (0)
Ver también
Categorías
Más información sobre Loops and Conditional Statements en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!