Warning: Matrix is close to singular or badly scaled. Results may be inaccurate.

i can't get the correct values for this calculation and i get the warning that Warning: Matrix is close to singular or badly scaled. Results may be inaccurate. a=[0,0.38,0.76,1.14,1.52,1.9,2.28,2.66,3.04,3.42,3.8; 0.38,0,0.38,0.76,1.14,1.52,1.9,2.28,2.66,3.04,3.42; 0.76,-0.38,0,0.38,0.76,1.14,1.52,1.9,2.28,2.66,3.04; 1.14,-0.76,-0.38,0,0.38,0.76,1.14,1.52,1.9,2.28,2.66; 1.52,-1.14,-0.76,-0.38,0,0.38,0.76,1.14,1.52,1.9,2.28; 1.9,-1.52,-1.14,-0.76,-0.38,0,0.38,0.76,1.14,1.52,1.9; 2.28,-1.9,-1.52,-1.14,-0.76,-0.38,0,0.38,0.76,1.14,1.52; 2.66,-2.28,-1.9,-1.52,-1.14,-0.76,-0.38,0,0.38,0.76,1.14; 3.04,-2.66,-2.28,-1.9,-1.52,-1.14,-0.76,-0.38,0,0.38,0.76; 3.42,-3.04,-2.66,-2.28,-1.9,-1.52,-1.14,-0.76,-0.38,0,0.38; 3.8,-3.42,-3.04,-2.66,-2.28,-1.9,-1.52,-1.14,-0.76,-0.38,0]; b=[2436009.4;1865655.99; 1295302.6; 724949.2; 154595.8; -415757.6; -986111.0; -1556464.4; -2126817.8; -2667152.6; -3267524.6]; c=a\b

[John D'Errico]

Sigh.

rank(a)
ans =
     2

size(a)
ans =
    11    11

rank([a,b])
ans =
     3

Go directly to linear algebra 101. Do not pass go. Do not collect $200.

Hint #1: There is no exact solution. And any solution you do get is no better than any other solution.

Hint #2: If you absolutely, positively insist on some "solution", try either pinv or lsqminnorm. But remember there are infinitely many equally bad solutions.

But first, return to linear algebra 101.