Borrar filtros
Borrar filtros

RLC Transfer Function Magnitude and Phase Response

10 visualizaciones (últimos 30 días)
1582251394
1582251394 el 23 de Sept. de 2018
Comentada: 1582251394 el 23 de Sept. de 2018
Hi,
I am trying to plot the magnitude and phase response for a parallel RLC circuit. The curves look close to what it should be but for the magnitude response, it peaks at 1MHz and I was expecting 3.55MHz (angular frequency). Also, my phase response looks ok but I am unable to get the curve to rotate 180 degrees on its axis.
clc;
syms L C R w
pretty(abs(w.*j*L*R./(w.*L*j+1+j^2*w.^2*C*L*R)));
L = 2e-9;
C = 1e-6;
R = 500;
w = linspace(0.99e6,1.01e6,10000);
j=sqrt(-1);
subplot(2,1,1);
Z1 = abs(w.*j*L*R./(w.*L*j+1+j^2*w.^2*C*L*R));
plot(w,Z1);
subplot(2,1,2);
w = linspace(2*pi,-2*pi,10000);
Z2 = angle(w.*j*L*R./(w.*L*j+1+j^2*w.^2*C*L*R));
plot(w,Z2);

Respuesta aceptada

David Goodmanson
David Goodmanson el 23 de Sept. de 2018
Hi 2e9,
I don't know why you feel that the resonant circular frequency (w) should be 3.55e6 since 1/sqrt(L*C) = 2.24e7. The main problem is the expression for Z, which should be
(w.*j*L*R./(w.*L*j + R + j^2*w.^2*C*L*R))
^
There had to be something wrong since the original expression is not correct on units and dimensions. If you change the plot range to
w = linspace(22.3e6,22.4e6,10000);
the resonance is where it should be.
  1 comentario
1582251394
1582251394 el 23 de Sept. de 2018
Thank you for noticing the mistake in the function. I originally had it in a different form and when I switched to this one, I forgot to add the R in the denominator. And for some reason, I was converting to frequency.

Iniciar sesión para comentar.

Más respuestas (0)

Categorías

Más información sobre Mathematics en Help Center y File Exchange.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by