Stretching a rectangle over a date axis
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Avi Michaely
el 23 de Sept. de 2018
Hello, I have a graph with dates as X axis (datetime variables) I'm trying to stretch a rectangle over certain dates (I have the dates stored in a vector), but the problem is that the X axis is datetime and the Y axis is doubles, so MATLAB throws an error. How can I fix this?
for I = 1:1:length(main_idleDateMat(:,1))
startX = main_idleDateMat(I,1);
endX = main_idleDateMat(I,2);
rectangle('Position', [startX idleVecStartHeights(I)-80 (endX - startX) 160]);
end
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dpb
el 23 de Sept. de 2018
Editada: dpb
el 24 de Sept. de 2018
Ayup, "no can do" it seems...another place TMW either hasn't yet got a round tuit or didn't think it needed to add an overloaded plotting function to take care of the new class object.
All is not lost, however, but it's a regression, indeed. :(
You'll have to revert to the venerable datenum form to plot to subsequently use rectangle or draw the lines directly with plot or line. If you do the former, then will have to also use datetick to format the x-axis as date. All in all, the direct-drawing option may turn out "more better".
ADDENDUM
Use patch. You'll have to provide X,Y vectors to outline the four corners, but it an aliased version has been created that is datetime-aware so TMW has, to their credit, done the most fundamental routine.
Mayhaps they'll eventually get to the rest...
3 comentarios
dpb
el 24 de Sept. de 2018
Editada: dpb
el 24 de Sept. de 2018
Yeah, the overloaded plot functions know what to do with the datetime or timeseries axes; it's still a work in progress for some of the other specialty routines.
Not clear whether they "just haven't got there yet" or nobody's really thought about such and have simply overlooked the other functions. Probably worth enhancement request/feature shortage/quality of implementation/bug report depending on one's point of view of how to judge the failure.
Más respuestas (3)
Ian
el 25 de Abr. de 2020
Editada: Ian
el 25 de Abr. de 2020
There's a nice solution to drawing a semi-transparent colored rectangle over a plot at https://stackoverflow.com/questions/45266078/how-to-draw-a-colored-rectangle-on-a-plot-when-x-axis-is-time
Alternately, you can use area(...) ,setting 'basevalue' to define the bottom of the rectangle:
area([dates(1),dates(2)],[.4,.4],'facecolor',[.8,1,.8], ...
'facealpha',.5,'edgecolor','none', 'basevalue',-.2);
will draw a rectangle with x values between dates(1) and dates(2), and y values between -.2 (basevalue) and .4 .
Stephen23
el 30 de Jun. de 2025
Editada: Stephen23
el 30 de Jun. de 2025
"How can I fix this?"
Use RULER2NUM, which converts from the ruler values (e.g. DATETIME) to numeric, correctly accounting for the ruler starting value:
ax = axes();
t = datetime(2015,1,1:10);
y = [0.2,0.3,0.5,0.2,0.8,0.2,0.3,0.1,0.3,0.4];
plot(ax, t,y,'-o')
x = ruler2num(t,ax.XAxis);
rectangle(ax, 'Position',[x(4),y(4),diff(x(4:5)),diff(y(4:5))], 'Curvature',[0.5,0.6])
Do not use DATENUM or other deprecated functions:

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Laurent
el 30 de Jun. de 2025
In case somebody still wants to use rectangle, it seems rectangle considers the origin as the low axis limit and the width in number of days (as datetime goes). Thus you have to work with your (rectangle) coordinates as difference from the low time axis limit. I tried plotting a month of data with the time being on x-axis and this works (at least for me):
% Defines dummy time series and plots
time = datetime( [2025 5 3] ) : 1/24 : datetime( [2025 5 28] );
data = rand( size( time ) );
plot( time, data, '.' ); XLim = xlim;
% Draws rectangle from May 15 to May 20 and 0.1 to 0.9
TimPos = datenum( diff( [ XLim(1) datetime( [2025 5 15; 2025 5 20] )' ] ) );
rectangle( 'Position', [ TimPos(1) 0.1 TimPos(2) 0.8 ] )
Be carefull: if you resize using zoom and want to redraw a rectangle, it is the original axis size that works (do not redo an xlim after zooming to determine the new TimPos).
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