Matching the maximum Values in a matrix from another vector
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I have a matrix with size of 21600 x 2 as Matrix_Vector = [STD_v,NPV_v]; I'm trying to find the values that matching xvalues = [0:.1:35] from STD_V.
So, I used this code:
[ d, ix ] = min( abs( STD_v-xvalues ) );
Matrix_Vector_updated = [STD_v(ix),NPV_v(ix)];
However, I still see values in Matrix_Vector_updated share the same values as 0.468 as below:
0.468490416082415 -68.0623566640544
0.468490416082415 -68.0623566640544
0.468490416082415 -68.0623566640544
0.468490416082415 -68.0623566640544
0.468490416082415 -68.0623566640544
0.468490416082415 -68.0623566640544
0.468490416082415 -68.0623566640544
0.861091227948802 -62.0460361812610
0.861091227948802 -62.0460361812610
0.920662009016715 -52.2025156248263
0.920662009016715 -52.2025156248263
1.08087425638995 -34.5197924821680
1.21018219911556 -45.0147047153047
1.31409003462488 -62.4048732765717
1.40064375002948 -49.6318599064140
1.50221080043184 -60.8266330903523
1.61795597497108 -48.3442487471706
1.68219041491832 -37.6318990471176
I'm trying to limit my numbers to the following format where I get only one value from NPV_v (the maximum if there is more than a value) corresponding to each value in STD_V:
0
0.100000000000000
0.200000000000000
0.300000000000000
0.400000000000000
0.500000000000000
0.600000000000000
0.700000000000000
0.800000000000000
0.900000000000000
1
Can anyone help please
4 comentarios
Stephen23
el 15 de Oct. de 2018
" I'm trying to find the values that matching xvalues = [0:.1:35] from STD_V."
Then you will probably run into floating point issues, and should use ismembertol or something similar.
Bruno Luong
el 15 de Oct. de 2018
@Stephen, I don't see any floatig point issue with
min( abs( STD_v-xvalues ) );
Yaser Khojah
el 15 de Oct. de 2018
Bruno Luong
el 15 de Oct. de 2018
"just want to select the maximum value"
I'm just unsure what you meant by that. You list a bunch of numbers without commenting where they come from.
And those number inside the odd IF
if true
....
end
This kind of language is not what I can read and interpret.
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