Code for equation with ln
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How can i Code it?
u=0.23 y=0.3 v=0.00001
u/u’=5*log(u’*y/v)-3.05
u’=?
I need to find the value of u’.

Respuestas (1)
Star Strider
el 21 de Oct. de 2018
Try this:
u=0.23;
y=0.3;
v=0.00001;
fcn = @(ustar,u,y,nu) 5*log(ustar.*y/nu)- 3.05 - u/ustar;
ustar = fsolve(@(ustar)fcn(ustar,u,y,v), 1)
ustar =
0.00918407730971717
2 comentarios
Sayeed
el 21 de Oct. de 2018
Star Strider
el 21 de Oct. de 2018
I already posted all the code that is needed to solve this problem.
You need to have the Optimization Toolbox installed to use fsolve.
You will have fminsearch regardless, so try using fminsearch on the norm of ‘fcn’:
ustar = fminsearch(@(ustar)norm(fcn(ustar,u,y,v)), 1)
ustar =
0.00918426513671787
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