I wrote this script
clc
clear
for ro=0.01:0.01:0.5
clear('alpha')
for alpha=0.25:0.25:4
clear('beta')
for beta=0.25:0.25:4
disp([ro', alpha',beta'])
end
when I run it and the result shows up it doesn't start with initial values which is (0.25,0.25) and take diffrent one each time i run the script thanks

 Respuesta aceptada

madhan ravi
madhan ravi el 24 de Oct. de 2018

0 votos

ro=0.01:0.01:0.5
alpha=0.25:0.25:4
beta=0.25:0.25:4
for i = 1:numel(ro)
for l = 1:numel(alpha)
for k = 1:numel(beta)
disp([ro(i)', alpha(l)',beta(k)'])
end
end
end

5 comentarios

Ammar kreem
Ammar kreem el 24 de Oct. de 2018
dear Madhan i tried your answer but the values dosnt start with 0.01 0.25 0.25 which i need to
madhan ravi
madhan ravi el 24 de Oct. de 2018
give an example of your output just few rows so the pattern what you require is understood
Ammar kreem
Ammar kreem el 24 de Oct. de 2018
dear Madhan this what I got 1.9100 1.0000 3.5000
1.9100 1.0000 3.7500
1.9100 1.0000 4.0000
and this what i need
0.01 0.25 0.25
0.01 0.25 0.5
and end with 2 4 4
thanks for everything
madhan ravi
madhan ravi el 25 de Oct. de 2018
You want to display the numbers like the below? 0.01 0.25 0.25
0.01 0.25 0.5
2 4 4
madhan ravi
madhan ravi el 25 de Oct. de 2018
disp([ro(i), alpha(l),beta(k)])

Iniciar sesión para comentar.

Más respuestas (1)

Ammar kreem
Ammar kreem el 25 de Oct. de 2018

0 votos

this how i want the result

Categorías

Más información sobre Loops and Conditional Statements en Centro de ayuda y File Exchange.

Productos

Versión

R2018a

Etiquetas

Preguntada:

el 24 de Oct. de 2018

Respondida:

el 25 de Oct. de 2018

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by