Following code is coming up with error "Array indices must be positive integers or logical values."
Does someone know what is causing this. Trying to store each value into an array
z =@(x) tan(x);
h = 0.5
for x=1:0.5:10
Output (x) = (z(x+h)-z(x-h))/(2*h);
end
Array = [Output]

1 comentario

Stephen23
Stephen23 el 25 de Oct. de 2018
Editada: Stephen23 el 25 de Oct. de 2018
Note that your code can be trivially vectorized (a loop is a waste of time):
z = @tan;
h = 0.5;
x = 1:0.5:10;
y = (z(x+h)-z(x-h))./(2*h);
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madhan ravi
madhan ravi el 25 de Oct. de 2018
Editada: madhan ravi el 25 de Oct. de 2018

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z =@(x) tan(x);
h = 0.5
x=1:0.5:10
Output = zeros(1,19) %preallocation for speed and efficiency
for i = 1:numel(x)
Output (i) = (z(x(i)+h)-z(x(i)-h))/(2*h);
end
Array = Output

3 comentarios

madhan ravi
madhan ravi el 25 de Oct. de 2018
you can access x(1.5)->(second iteration) because indexing should be real integers
Stephen23
Stephen23 el 25 de Oct. de 2018
@madhan ravi: where is the array preallocation? What do those square brackets do? (Hint: nothing)
madhan ravi
madhan ravi el 25 de Oct. de 2018
Thank you Stephen (edited now)

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