dsearchn() Command is slowing down my algorithm, Any better Solution? MATLAB

I am using the following code to calculate altitude.
Data = [Distance1',Gradient];
Result = Data(dsearchn(Data(:,1), Distance2), 2);
Altitude = -cumtrapz(Distance2, Result)/1000;
Distance 1 and Distance 2 has different size with same values so I am comparing them to get corresponding value of Gradient to use with Distance 2.
Just to execute these 3 lines the Matlab takes 12 to 15 seconds. Which slow down my whole algorithm.
Is there any better way I can perform above action without slowing down my algorithm?

11 comentarios

Yeah of course, almost anything else is better, why on earth are you using DSEARCHN for numbers? Use INTERP1 with 'nearest' option.
Can you please elaborate with an example in my case how should i use it?
Bruno Luong
Bruno Luong el 26 de Oct. de 2018
Editada: Bruno Luong el 26 de Oct. de 2018
Other way around: first you give us a (small) example.
Shahab Khan
Shahab Khan el 26 de Oct. de 2018
Editada: Shahab Khan el 26 de Oct. de 2018
I believe I already have given an example in my question about what i am trying to do.
You give a piece of code, without telling the size the class of your Data. No one can run your code if copy/past in MATLAB. Almost useless for people who tries to answer the question.
An "example" is some extra instruction to generate a small piece data, (and eventually an expecting output if the code is buggy and does not produce what you expect).
Apologies.
Here is my example.
Distance2= [1:10:1000]';
Distance1= [1:1:1000]';
Gradient= rand(1000,1);
Data= [Distance1,Gradient];
Result = Data(dsearchn(Data(:,1), Distance2), 2);
Replace
dsearchn(Data(:,1), Distance2)
by
interp1(Distance1,Distance2,'nearest');
This gives me distance values, I actually required gradient values from second column of Data corresponding to Distance1 in Data compared to Distance2 values.
For example, If Distance2 value is equal to Distance1 value in Data choose the corresponding value from second column in Data.
This command worked actually.
Result = interp1(Data(:,2),Distance2,'nearest');
Thank you for your help
I wrote replace just the DSEARCH, not the rest.
If you want to get the same Result as with
Data = [Distance1',Gradient];
Result = Data(dsearchn(Data(:,1), Distance2), 2);
and Data is just temporary variable and you don' mind to trash it away after, then
Result = interp1(Distance1,Gradient,Distance2,'nearest');

Iniciar sesión para comentar.

 Respuesta aceptada

Bruno Luong
Bruno Luong el 27 de Oct. de 2018
Editada: Bruno Luong el 27 de Oct. de 2018
Replace
dsearchn(Data(:,1), Distance2)
by
interp1(Distance1,Distance2,'nearest');
If you want to get the same Result as with
Data = [Distance1',Gradient];
Result = Data(dsearchn(Data(:,1), Distance2), 2);
and Data is just temporary variable and you don' mind to trash it away after, then
Result = interp1(Distance1,Gradient,Distance2,'nearest');

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el 26 de Oct. de 2018

Editada:

el 27 de Oct. de 2018

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