dsearchn() Command is slowing down my algorithm, Any better Solution? MATLAB
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I am using the following code to calculate altitude.
Data = [Distance1',Gradient];
Result = Data(dsearchn(Data(:,1), Distance2), 2);
Altitude = -cumtrapz(Distance2, Result)/1000;
Distance 1 and Distance 2 has different size with same values so I am comparing them to get corresponding value of Gradient to use with Distance 2.
Just to execute these 3 lines the Matlab takes 12 to 15 seconds. Which slow down my whole algorithm.
Is there any better way I can perform above action without slowing down my algorithm?
11 comentarios
Bruno Luong
el 26 de Oct. de 2018
Yeah of course, almost anything else is better, why on earth are you using DSEARCHN for numbers? Use INTERP1 with 'nearest' option.
Shahab Khan
el 26 de Oct. de 2018
Bruno Luong
el 26 de Oct. de 2018
Editada: Bruno Luong
el 26 de Oct. de 2018
Other way around: first you give us a (small) example.
Shahab Khan
el 26 de Oct. de 2018
Editada: Shahab Khan
el 26 de Oct. de 2018
Bruno Luong
el 27 de Oct. de 2018
You give a piece of code, without telling the size the class of your Data. No one can run your code if copy/past in MATLAB. Almost useless for people who tries to answer the question.
An "example" is some extra instruction to generate a small piece data, (and eventually an expecting output if the code is buggy and does not produce what you expect).
Shahab Khan
el 27 de Oct. de 2018
Bruno Luong
el 27 de Oct. de 2018
Editada: Bruno Luong
el 27 de Oct. de 2018
Replace
dsearchn(Data(:,1), Distance2)
by
interp1(Distance1,Distance2,'nearest');
Shahab Khan
el 27 de Oct. de 2018
Shahab Khan
el 27 de Oct. de 2018
Bruno Luong
el 27 de Oct. de 2018
Editada: Bruno Luong
el 27 de Oct. de 2018
I wrote replace just the DSEARCH, not the rest.
If you want to get the same Result as with
Data = [Distance1',Gradient];
Result = Data(dsearchn(Data(:,1), Distance2), 2);
and Data is just temporary variable and you don' mind to trash it away after, then
Result = interp1(Distance1,Gradient,Distance2,'nearest');
Shahab Khan
el 27 de Oct. de 2018
Respuesta aceptada
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