How to solve an linear set of equations with arbitrary number of symbolic elements

I defined my U, with an arbitrary lenght due to the preferable N_elements

U = sym('U',[N_elements+1 1]);

Now I want to solve my linear set of equations by

FU_antwoord = solve(eq,[U(2), U(3), U(4), U(5)]);

This works, but only for N_elements= 4. Now I tried to make it work for an arbitrary chose N_elements, with a dummy-element U_t

U_t = U';
FU_antwoord = solve(eq,[ U_t(2:end)]

But this did not work (since the symbolic elements get transposed?), giving the error: Second argument must be a vector of symbolic variables.

Anyone know how I can solve this?

[Matt J]

This works, but only for U = 4.

Do you mean only for N_elements=4?

[Frank Oosterveld]

You are right!

[Frank Oosterveld]

Concludingly, I want to make an script such that ,

FU_antwoord = solve(eq,[F(1), U(2), U(3), U(4), U(5)])

Becomes for N_elements =5

FU_antwoord = solve(eq,[F(1), U(2), U(3), U(4), U(5), U(6)])

N_elements =6

FU_antwoord = solve(eq,[F(1), U(2), U(3), U(4), U(5), U(6), U(7)])

etcetera

[Walter Roberson]

[F(1), U(2:end-1).']

Answer 1

[Walter Roberson]

U_t = U.';

Remember that the ' operator is conjugate transpose.