How to choose values in the second and third column corresponding to the drawn numbers?
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hawk5577
el 15 de Nov. de 2018
Respondida: Bruno Luong
el 17 de Nov. de 2018
%N X Y
AA=[ 1 0 4
2 1 5
21 4 6
81 3 7
92 7 8
73 6 4
65 3 3
36 5 4
16 6 5
6 7 4]
A=AA(:,1);
disp(A);
b=(A(randperm(size(A,1),3),1))
disp(b);
% How to choose values in the second and third column corresponding to the drawn numbers?
for i=1:3 %This solution give me error - Index in position 1 exceeds array bounds (must not exceed 10).
c=b(i,1);
disp(AA(c,2));
disp(AA(c,3));
end
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Respuesta aceptada
Arunkumar M
el 17 de Nov. de 2018
Editada: madhan ravi
el 17 de Nov. de 2018
Error occurs because with c you are finding the element which is a part of first column in AA. But this element is not the index. So you have to find the index where it is located and then pull out second and third column values.
for i=1:3
c=b(i,1);
temp1 = find(A == c);
temp2 = temp1(1,1); % in case multiple values are returned in temp1.
disp(AA(temp2,2));
disp(AA(temp2,3));
end
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Bruno Luong
el 17 de Nov. de 2018
Why make so complicated? RANDPERM returns the position, store and use it rather than trying to recover it.
AA=[ 1 0 4
2 1 5
21 4 6
81 3 7
92 7 8
73 6 4
65 3 3
36 5 4
16 6 5
6 7 4]
p = randperm(size(A,1),3);
b = AA(p,1)
AA(p,:)
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