Adding sparse matrices efficiently?
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Hi, I have a cell array which consists of many sparse matrices. For example:
N.B. In my original problem each sparse matrix is about 4000*4000 in size and has many zero entries
A{1}=sparse(magic(150));
A{2}=sparse(magic(150));
A{3}=sparse(magic(150));
A{4}=sparse(magic(150));
....
% I want something like:
KK = A{1}+A{2}+A{3}+....
% KK should be a sparse matrix of 150*150
% Adding them in a loop is very time consuming
% I tried the following but did not work:
KK = sum(cat(2,KC{:}),3); % or 1,2 as the sum dimension
% also
KK = sum([KC{:}]); % gives a vector
2 comentarios
David Goodmanson
el 17 de Nov. de 2018
Hi Mohammod,
It's not going to be a good idea to use sparse(magic(N)) as a benchmark for timing. This matrix is stored in the sparse convention but is absolutely not sparse, since it has no nonzero elements at all. Sparse has to do a lot of work in that case.
sparse(magic(N)) + sparse(magic(N)) takes more time than the addition of the full matrices, magic(N) + magic(N).
Mohammod Minhajur Rahman
el 17 de Nov. de 2018
Respuesta aceptada
Más respuestas (1)
Bruno Luong
el 17 de Nov. de 2018
Editada: Bruno Luong
el 17 de Nov. de 2018
The fatest way to add sparse matrices is to build the sum from scratch.
It takes 4 second for 1000 random matrices of 4000x4000 with density 1e-3.
I = [];
J = [];
V = [];
n = 0;
for k = 1:length(A)
[i,j,v] = find(A{k});
p = n + numel(i);
m = numel(I);
if p > m
m = max(p,2*m);
I(m) = 0;
J(m) = 0;
V(m) = 0;
end
idx = (n+1:p);
I(idx) = i;
J(idx) = j;
V(idx) = v;
n = p;
end
idx = (n+1:numel(I));
I(idx) = [];
J(idx) = [];
V(idx) = [];
[m,n] = size(A{1});
SUM = sparse(I,J,V,m,n)
1 comentario
Mohammod Minhajur Rahman
el 19 de Nov. de 2018
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