Checking if a matrix is symmetric

Hi
i want to check if the matrix is symmetric or not by using nested loops and display a certain message if it is or not. the problem is that it's displaying the message after comparing each element of the original matrix with the ones in the transposed or inversed matrix.. i want the message to be displayed after both matrices are compared!.
A = [ 2 6 9; 7 3 8; 10 11 12];
for i = 1:3
for j = 1:3
if(A(i,j) == A(j,i))
disp('true')
else
disp('false')
end
end
end

 Respuesta aceptada

Bruno Luong
Bruno Luong el 26 de Nov. de 2018
disp(isequal(A,A.'))

9 comentarios

it printed zeros.. what im looking for is that it prints one of the following :
disp('The matrix is symmetric!');
%or
disp('The matrix is asymmetric!');
fprintf(['The matrix is a' repmat('\b',isequal(A,A.')) 'symmetric!\n'])
Abdulelah  Jo
Abdulelah Jo el 26 de Nov. de 2018
thank you so much.. how can i make it print the command once?
Walter Roberson
Walter Roberson el 26 de Nov. de 2018
? That already displays the output once.
Abdulelah  Jo
Abdulelah Jo el 26 de Nov. de 2018
it displays it three times! Where i should include the print statement?
Walter Roberson
Walter Roberson el 26 de Nov. de 2018
Editada: Walter Roberson el 26 de Nov. de 2018
I suspect that you put Bruno's code into a loop. Instead it should be the entire code. It does it all including the displaying. No loop.
A = [ 2 6 9; 7 3 8; 10 11 12];
fprintf(['The matrix is a' repmat('\b',isequal(A,A.')) 'symmetric!\n']);
Abdulelah  Jo
Abdulelah Jo el 26 de Nov. de 2018
i want the matrix to be checked with nested loops.. that's what im trying.... Bruno's Answer does work but with loops it repeats the message!
A = [ 2 6 9; 7 3 8; 10 11 12];
for i = 1 : 1
for j = 1 : 1
fprintf(['The matrix is a' repmat('\b',isequal(A,A.')) 'symmetric!\n']);
end
end
Abdulelah  Jo
Abdulelah Jo el 26 de Nov. de 2018
Thanks alot! it worked <3

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